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ELEN [110]
3 years ago
5

What number should come next ?

Mathematics
1 answer:
babymother [125]3 years ago
3 0
<h2>Answer: <u>The number that comes next is 52 </u></h2>

Step-by-step explanation:

2 + (1^2 - 1 ) = 2

2 +( 2^2 - 1 ) = 5

5 + ( 3^2 - 1) = 28

28 + (5^2 - 1) = 52

Thus the next number would be 52

Hope this helps :D

You might be interested in
A shop rents a DVD player at $10 per day and a charged a later fee of $15 for every day it is late. If Timmy renter a DVD player
Assoli18 [71]

Answer:

$130

Step-by-step explanation:

Renting the dvd for one day costs $10.

$15 is charged for every late day .

Timmy rented the DVD player for 4 days and returned it 10 days later.

For 4 days , the amount

= $10 x 4

= $40

For the remaining six days he’ll pay

$15 x 6= $90 because he was charged the late fee .

Therefore, total amount paid by Trimmy

= $40 + $90

= $130

Trimmy paid $130

8 0
3 years ago
Find AC if AB = 1, AC = 2x + 26, and BC = x + 16
Keith_Richards [23]

Answer:

8

Step-by-step explanation:

AC=AB+BC

2X+26=1+x+16

2x-x=1+16-26

X= - 9

Now, AC=2X+26

=2*-9+26

= - 18+26

=8

6 0
3 years ago
A local water storage facility is currently empty. The city
Semenov [28]

Answer: See explanation

Step-by-step explanation:

a) How much-water will be in the water storage facility in 25 minutes?

Since the city water workers begin filling it at a rate of 500 gallons per minute, in 25 minutes they'll have filled:

= 500 × 25

= 12500 gallons

It immediately begins sending some of its water into the city's water pipes at a rate of 150 gallons per minutes. In 25 minutes, they'll have sent:

= 150 × 25

= 3750 gallons

Amount that'll be left in the tank will be:

= 12500 - 3750

= 8750 gallons

b. Write an equation to find the number of gallons,y,in the storage facility after x minutes. This will be:

y = (500 × x ) - (150 × x)

y = 500x - 150x

y = 350x

7 0
3 years ago
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
So somebody said those were the answers but i don’t think they are correct.
oksano4ka [1.4K]
I would speak to my friend or pen pal or the person your working with and come up to an agreement. That is my advice
6 0
3 years ago
Read 2 more answers
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