Sqrt14 = 3.74 (2dp)
The principal root is always the positive.
Answer:
The zeros are 0, 4, 6.
The y-intercept is 0.
Step-by-step explanation:
f(x) = x^3 - 10x^2 + 24x
x^3 - 10x^2 + 24x = 0
x(x^2 - 10x + 24) = 0
x(x - 4)(x - 6) = 0
x = 0 or x - 4 = 0 or x - 6 = 0
x = 0 or x = 4 or x = 6
y-intercept:
Since x = 0 is a root, that means that the point (0, 0) is part of the function. That makes the y-intercept 0.
You can also solve for the y-intercept by letting x = 0 in the function and solving for f(0).
Let x = 0.
f(0) = 0^3 - 10(0^2) + 24(0)
f(0) = 0
y-intercept: 0
Answer:
1.188
Step-by-step explanation:
19 ounces = 1.875
1.875 rounded is 1.88
answer = 1.88
couldn't help as much due to the fact you didn't add how much the dog gains
Answer: 196pi in.^2
Step-by-step explanation:
Divide the diameter by two.
You would get 14, then square it, you would get 196.
Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is 
is correct answer
Therefore ![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2%3D%5Cfrac%7B1%7D%7B3%5E8%7D)
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
( using the property 
)
( using the property 
( combining the like powers )
( using the property 
)
( using the property 
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is is correct answer
