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Masja [62]
2 years ago
11

Find the scale factor of a model school bus if the scale is .5 inches=7feet.

Mathematics
1 answer:
LenKa [72]2 years ago
6 0

Answer: 168

Step-by-step explanation: A scale factor is simply the ration between two corresponding units, therefore you can just divide the units by each other. There are 12 inches in a foot, 84 in 7 feet. 85/.5=168

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Help me plz I need it I'm very desperate help
Klio2033 [76]

Answer:

1/45

Step-by-step explanation:

There are 10 marbles

P ( yellow) = yellow marbles / total = 2/10 = 1/5

We do not replace the marble

There are 9 marbles, 1 of which is yellow

P ( yellow) = yellow marbles / total = 1/9

P ( yellow, no replacement, yellow) = 1/5 * 1/9 = 1/45

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Answer by today!!! x^2 + (2y) ÷ (2w) + 3z w = 2, x = 5, y = 8, z = 3
inysia [295]

Answer:

4.1

Step-by-step explanation:

5^2 + (2*8) / (2*2) + 3*3

25 + 16 / 4 + 6

41 / 10

4.1

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2 years ago
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Can you please explain ME how to solve identity of algebra homework ​
yKpoI14uk [10]

Step-by-step explanation:

"identity" means an operation that does nothing.

For adding numbers, adding 0 changes nothing, so 0 is the identity for addition.

For multiplication, multiplying by 1 changes nothing, so 1 is the identity for multiplication.

3 0
3 years ago
How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

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