Answer:
y = 2cos5x-9/5sin5x
Step-by-step explanation:
Given the solution to the differential equation y'' + 25y = 0 to be
y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.
According to the boundary condition y(0) = 2, it means when x = 0, y = 2
On substituting;
2 = c1cos(5(0)) + c2sin(5(0))
2 = c1cos0+c2sin0
2 = c1 + 0
c1 = 2
Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given
y(x) = c1cos5x + c2sin5x
y'(x) = -5c1sin5x + 5c2cos5x
If y'(π) = 9, this means when x = π, y'(x) = 9
On substituting;
9 = -5c1sin5π + 5c2cos5π
9 = -5c1(0) + 5c2(-1)
9 = 0-5c2
-5c2 = 9
c2 = -9/5
Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation
y = c1 cos(5x) + c2 sin(5x) will give
y = 2cos5x-9/5sin5x
The final expression gives the required solution to the differential equation.
Answer:
see explanation
Step-by-step explanation:
The opposite angles of an inscribed quadrilateral are supplementary, thus
5x + 20 + 7x - 8 = 180
12x + 12 = 180 ( subtract 12 from both sides )
12x = 168 ( divide both sides by 12 )
x = 14
Thus
∠ RQP = 10x = 10(14) = 140°
∠PSR = 180° - 140° = 40° ( opposite angles are supplementary )
∠ SRQ = 7X - 8 = 7(14) - 8 = 98 - 8 = 90°
∠ QPS = 5x + 20 = 5(14) + 20 = 70 + 20 = 90°
If x=students, the equation would be x=12 (x is less than of equal to twelve). I don’t know what you mean by constraints; perhaps if you explain more, I could help?
Hello!
The formula for finding area of a circle is: π · r²
Diameter is 2x the radius. To find the radius when the diameter is given, divide the diameter by 2.
The diameter is 13. 13 ÷ 2 = 6.5
r = 6.5
6.5² = 6.5 × 6.5 = 42.25
π = 3.14
Multiply 3.14 by 42.25 to get the area
3.14 × 42.25 = 132.665
<em>The area of the circle is 132.665 sq. units, which is the last option.</em>
The answer is D. Sorry for taking so long
