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Anit [1.1K]
3 years ago
8

Write a variable expression for 9 more than a number s.

Mathematics
1 answer:
Vladimir [108]3 years ago
7 0
S+9

More than suggests addition.
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Find this value for brainiest <br> 1+9^14
r-ruslan [8.4K]

Answer: 2.2876792e+13

Step-by-step explanation: calculator

6 0
3 years ago
a packe of cards conatins 4 red and 5 black cards. a hand of 5 cards is drawn without replacment. What is the proablity of all f
Vladimir79 [104]

Answer: Our required probability is 0.3387.

Step-by-step explanation:

Since we have given that

Number of red cards = 4

Number of black cards = 5

Number of cards drawn = 5

We need to find the probability of getting exactly three black cards.

Probability of getting a black card = \dfrac{5}{9}

Probability of getting a red card = \dfrac{4}{9}

So, using "Binomial distribution", let X be the number of black cards:

P(X=3)=^5C_3(\dfrac{5}{9})^3(\dfrac{4}{9})^2\\\\P(X=3)=0.3387

Hence, our required probability is 0.3387.

5 0
3 years ago
Andy joins a social networking site. After day three, he has 25 friends; after day eight, he has 40 friends. Write the equation
Allisa [31]

Answer:

Point slope intercept form: The equation for line is given by; y-y_1=m(x-x_1) ......[1] ; where m is the slope and a point (x_1, y_1) on the line.

Let x represents the number of days and y represents the number of friends.

As per the statement:  After day three, he has 25 friends; after day eight, he has 40 friends.

⇒ We have two points i.e,

(3, 25) and (8, 40)

First calculate slope(m);

m = \frac{y_2-y_1}{x_2-x_1}

Substitute the given values we get;

m = \frac{40-25}{8-3}=\frac{15}{5} = 3

now, substitute the given values of m=3 and a point (3, 25) in [1] we get;

y-25=3(x-3)

Using distributive property; a \cdot(b+c) = a\cdot b + a\cdot c

y-25 = 3x - 9

Add 25 on both sides, we get;

y-25+25 = 3x - 9+25

Simplify:

y =3x + 16

if  x = 18 days, then;

y = 3(18) + 16 = 54+16 = 70

Therefore, he will have on day 18, if he continues to add the same number of friends each day is, 70 friends.

7 0
3 years ago
What is the tan invers of 3i/-1-i​
postnew [5]

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )

<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))

<em>z</em> = (-3 - 3<em>i </em>) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have

arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>

arg(<em>z</em>) = arctan(1) - <em>π</em>

arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>

arg(<em>z</em>) = -3<em>π</em>/4

where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.

6 0
2 years ago
What is 4876510×7928670
myrzilka [38]
4876510*7928670  \text{Multiplication} 

\text{Solution = }38664238541700

5 0
3 years ago
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