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yKpoI14uk [10]
3 years ago
13

le" class="latex-formula">
Mathematics
1 answer:
barxatty [35]3 years ago
3 0
9x^2 -6x +1+12=0
9x^2 -6x +13=0
factorise
(3x-1)(3x-1) =0
so, x= 1/3
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Nicholas has a fish tank that is 12 inches high, 14.5 inches long, and 6.5 inches wide. If he fills the tank halfway with water,
natulia [17]

Answer:

565.5 in^3

Step-by-step explanation:

To find the full volume of the tank

V = l*w*h

We know 12 inches high, 14.5 inches long, and 6.5 inches wide.

Substituting in

V = 12 * 14.5*6.5

V =1131 in ^3

He is filling it 1/2 full, that would be 1/2 of the volume

1/2 V = 1131/2 = 565.5 in^3

5 0
4 years ago
Read 2 more answers
An item is regularly priced at $97 . Alonzo bought it at a discount of 85% off the regular price. wats the price now
siniylev [52]

Answer:

at least above 3$

Step-by-step explanation:

5 0
3 years ago
Two friends, Hailey and Jenna bought two tickets to see a play at a local theater . Each ticket cost $17.25. Each friend donated
Gennadij [26K]
If you let the convenience fee equal x, then...

(2×17.25)+(2×1)+(2×x)= 40.50

There are 2 girls so we multiply all the charges by 2. Add them together and you'll get 40.50. Now if we solve for x, we will get the amount of the convenience fee.

2×17.25 + 2×1 + 2x = 40.50
34.50 + 2 + 2x = 40.50
36.50 + 2x = 40.50
2x = 40.50 - 36.50
2x = 4
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Each girl paid a 2 dollar convenience fee.
6 0
3 years ago
A woman put $580 into a savings account for one year. the rate of interest on the account was 61 1/2%. how much was the interest
sdas [7]
580 x 0.065=$37.70 total interest
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3 0
3 years ago
A building is of unknown height. At a distance of 400 feet away from the building, an observer notices that the angle of elevati
Harman [31]

Given :

A building is of unknown height. At a distance of 400 feet away from the building .

An observer notices that the angle of elevation to the top of the building is 35º and that the angle of elevation to a poster on the side of the building is 15º .

To Find :

How far is the poster from the roof of the building .

Solution :

Height is given by :

h=d\times tan\theta

( Here , \theta is angle of elevation )

So , height of tower :

H=400\times tan 35^o\\\\H=280.08 \ feet

For height of poster :

h=400\times tan 15^o\\\\h= 107.18\ feet

Therefore , distance of poster from the roof of the building is :

( 280.08-107.18)  =  $$172.9\ feet

Hence , this is the required solution .

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4 years ago
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