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arlik [135]
3 years ago
12

PLEASE HELP FAST

Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0
Not sure sorryyyyyyyyyyyyyy
Yyyyyyyy
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write an equation of the line, in slope intercept form, that passes through the given point and has the given slope. point:(8,-8
denis23 [38]
If m equals 3, and we have a y and x value of 8 and -8, all we have to do is solve for b.

-8 = 3(8) + b
Multiply 8 and 3.
-8 = 24 + b
Subtract 24 from both sides to isolate b.
-32 = b

Your equation would look like this:

y = 3x - 32
3 0
4 years ago
Help please me with this
liraira [26]

Answer:

15

Step-by-step explanation:

with 90 spins and 6 probabilities...

90 ÷ 6

= 15

5 0
4 years ago
Need help with one and two
adoni [48]

Answer:

(1) is a function, surjective aka onto,

not bijective aka one to one.

domain is {3,6,12,14,20,22},

range is {4,15,8,11}. More elements in domain means it can't possibly be one to one.


(2) is a relation but not a function, although its inverse is a function. There are fewer elements in the domain than the range, so a function could not be onto but would have to be into or injective.


The relation you get by restricting the domain to {1,19} is a function, injective, so that the image of the domain is a proper subset of the range.


7 0
3 years ago
AB is parallel to CD. EG = FG ˆ AEG = 110° ˆ Calculate the size of DGH.
Sever21 [200]

Opposite exterior angles are congruent.

DGH = AEG

DGH = 110

3 0
3 years ago
Find the volume of the cone in cubic feet. Use 3.14 for it and round your answer to the nearest tenth.
kenny6666 [7]
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

\quad\hookrightarrow\quad \sf {5,790,806.5\:ft^3 }

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ:</u></h3>

Here, we area provided a cone with:

  • Radius = 48m
  • Height = 68 m

We have to find the volume of the cone in feet³, and we are given that 1m = 3.2808ft

<h3><u>Ⳙ⳽ⲓⲛⳋ ⳨ⲟⲅⲙⳙ</u><u>ⳑɑ</u><u>:</u></h3>

The volume of a cone is equal to one third of the volume of a cylinder having the same base radius and height ,i.e:

\quad\longrightarrow\quad \sf { V =\dfrac{1}{3}\pi r^2 h }

<u>Therefore</u><u>,</u><u> </u><u>Volume:</u>

\implies\quad \tt {V = \dfrac{1}{3}\pi r^2 h }

\implies\quad \tt { V =\dfrac{1}{3}\times 3.14 \times 48^2 \times 68 }

\implies\quad \tt { V =\dfrac{1}{\cancel{3}}\times 3.14\times \cancel{2304} \times 68}

\implies\quad \tt {V =3.14\times 768\times 68 }

\implies\quad \tt {V = 163,983.36}

\implies\quad \tt { V = 163,983.36 \times (3.2808)^3 \qquad\quad\bigg[ As, \: 1m = 3.2808ft\bigg]}

\implies\quad \tt {V = 163,983.36\times 35.30 }

\implies\quad\underline{\pmb{ \tt { V = 5,790,806.5 ft^3}}}

‎ㅤ‎ㅤ‎ㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>volume </u><u>of </u><u>given </u><u>cone </u><u>is </u><u>5,790,806.5</u><u> </u><u>f</u><u>t</u><u>³</u><u>.</u>

3 0
3 years ago
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