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sashaice [31]
3 years ago
9

Find the sum of (1-1/n) + (1-2/n) + (1 - 3/n)....upto n terms

Mathematics
1 answer:
bija089 [108]3 years ago
4 0

Answer:

<em> (n - 1)/2</em>

Step-by-step explanation:

F = (1 - 1/n) + (1 - 2/n) + (1 - 3/n) + ...(1 - n/n)

  = (1 + 1 ... + 1) - (1/n + 2/n + 3/n + ...n/n)

     (there are n terms of 1)

  = n - (1 + 2 + 3 + ... + n)/n

  = n - [n x (n + 1)/2]/n

  = n - [n x (n + 1)]/[2 x n]

  = n - (n+1)/2

  = (2n - n - 1)/2

  = (n - 1)/2

Hope this helps!

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Answer:

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Step-by-step explanation:

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The easiest way to factor is to find two numbers of the "a" value (the coefficient before x^{2}) and the factors of the c value (10) that ADD up to give you -9, in this case it would be:

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You could stop here and conclude that this is not factorable by inspection.

Another method: using the quadratic formula to find its roots.

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