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timurjin [86]
3 years ago
14

HELP! How do you do this!! Need help ASAP!!

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Multiplying binomial and polynomials can be easy as long as you follow the steps for example:

Let's say you were multiplying 3x-3 and x+2

(3x-3)(x+2)

remember FOIL

OR think about it like this(see attatchment)

3x^2 + 3x -6 is what you should get

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Simplify. 14+{−2+3[1+3(−6−2)]} show how to solve as well with answer
frez [133]
It’s -57 thank me later
3 0
4 years ago
Read 2 more answers
Which best describes the numbers satisfying the inequality x <7?
likoan [24]

Answer:

(B) all numbers less than 7

Step-by-step explanation:

Given the inequality:

x<7

It means that:

  • x cannot be equal to 7
  • x cannot be greater than 7

Therefore, x<7 consists <u>of all numbers less than 7.</u>

3 0
3 years ago
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How we supposed to find the answer?
Gnoma [55]

Answer:

5^6

Step-by-step explanation:

(5^3)^2

We know that a^b^c = a^(b*c)

5^(3*2)

5^6

8 0
3 years ago
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Mrs. Aguirre is going to plant a rectangular garden in her rectangular backyard, as
pantera1 [17]

Answer:

The answer is below

Step-by-step explanation:

From the image attached we can see that the width of the garden is 6 ft. The length of the garden is the slanting side of the triangle (hypotenuse).

Let x be the length of the garden. The height of the triangle = 40 ft - 15 ft = 25 ft.

The base of the triangle = 80 ft - 75 ft = 5 ft.

The length of the garden is gotten using Pythagoras:

x² = 25² + 5²

x² = 650

x = 25.5 ft.

The area of the garden = length * width = 25.5 * 6 = 153 ft²

Hence the approximate area = 160 ft²

4 0
3 years ago
Display the set of data in a histogram.
VARVARA [1.3K]

Answer:

The answer to your question is the third histogram

Step-by-step explanation:

What we must check in a histogram is that the x-axis is represented the intervals and in the y-axis is represented the frequency.

The first histogram is incorrect just by observing the first bar, we notice that the correct frequency from 0 to 4 is 3, not 14. This histogram is incorrect.

Also, the second histogram is incorrect, the frequency of the first category is 3, not 12. This histogram is wrong.

The third histogram is correct because all the bars are in agreement with their frequencies.

The last histogram is incorrect, for example, the last frequency is 12, not 3.

4 0
3 years ago
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