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3 years ago

Round 231469.335329 to the nearest thousand

Mathematics

2 answers:

malfutka [58]3 years ago

8 0

Answer: 231,469.335

Step-by-step explanation:

sdas [7]3 years ago

7 0

Answer:

23200

Step-by-step explanation:

Always remember that any value equals or greater than 5 can be rounded up as 1

So any value less than 5 will actually equals to zero

According to the question,231469.335329

So let's start from the decimal point

Since 3 is less than 5 it will be equals to zero

So we will have 231469

Remember we are to round up to thousand

So we will have to deal with 469

9 is greater than 5 so it will give 1

470

And 7 is greater than 5 we will 1

500

So we will have 231500

This has been rounded up to hundred but the question says thousand

So to thousand we will have 232000

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Which number is missing from the following prime factorization expression? 792 = __ x 2 x 2 x 2 x 3 x 11 A. 2 B. 3 C. 5 D. 7

lions [1.4K]

Answer:

Step-by-step explanation:

Evaluate 2 x 2 x 2 x 3 x 11 (better written as 2·2·2·3·11, because "x" is a variable name, not a math operator).

2·2·2·3·11 = 8·33 = 264

Then divide 792 by this 264 to find the final factor:

final factor = 792/264 = 3

Then the prime factorization of 792 is 2·2·2·3·3·11

which we obtained by multiplying 2 x 2 x 2 x 3 x 11 by 3.

7 0

3 years ago

Read 2 more answers

Hey hun can any of y'all help me?

11111nata11111 [884]

$\bf \cfrac{5}{\frac{1}{6}+\frac{1}{x+1}}\qquad \cfrac{}{\impliedby LCD\textit{ will be 6(x+1)}}\implies \cfrac{5}{\frac{1(x+1)+1(6)}{6(x+1)}}
\\\\\\
\cfrac{5}{\frac{x+1+6}{6(x+1)}}\implies \cfrac{\frac{5}{1}}{\frac{x+7}{6(x+1)}}\implies \cfrac{5}{1}\cdot \cfrac{6(x+1)}{x+7}\implies \cfrac{30(x+1)}{x+7}$

and you can expand the numerator if you wish, it won't be simplified further though.

6 0

3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!

Artyom0805 [142]

The recursive formula for f(n) is f(n) = 4.25 + f(n - 1), f(0) = 2.25.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let f(n) represent the total cost of shoe rentals for n games, hence:

The recursive formula for f(n) is f(n) = 4.25 + f(n - 1), f(0) = 2.25.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0

2 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago

How can you identify unit rate from a table, equation and graph

Zina [86]

Answer:

hiiii

Step-by-step explanation:

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8 0

3 years ago