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3 years ago

Round 231469.335329 to the nearest thousand

Mathematics

2 answers:

malfutka [58]3 years ago

8 0

Answer: 231,469.335

Step-by-step explanation:

sdas [7]3 years ago

7 0

Answer:

23200

Step-by-step explanation:

Always remember that any value equals or greater than 5 can be rounded up as 1

So any value less than 5 will actually equals to zero

According to the question,231469.335329

So let's start from the decimal point

Since 3 is less than 5 it will be equals to zero

So we will have 231469

Remember we are to round up to thousand

So we will have to deal with 469

9 is greater than 5 so it will give 1

470

And 7 is greater than 5 we will 1

500

So we will have 231500

This has been rounded up to hundred but the question says thousand

So to thousand we will have 232000

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Calculate cos(480°) and sin(480°).

hram777 [196]

Answer:

$\cos(480^\circ)=-\dfrac{1}{2}$

$\sin(480^\circ)=\dfrac{\sqrt{3}}{2}$

Step-by-step explanation:

Calculate the value of trigonometry function.

$\cos(480^\circ)$ and $\sin(480^\circ)$

Split the angle between 0 to 90° using trigonometry formula.

$\Rightarrow \cos(360^\circ+120^\circ)$

$\Rightarrow \cos(120^\circ)$ $\because \cos(360+\theta)=\cos\theta$

$\Rightarrow \cos(180^\circ-60^\circ)$ $\because 120=180-60$

$\Rightarrow -\cos(60^\circ)$ $\because \cos(180-\theta)=-\cos\theta$

$\Rightarrow -\dfrac{1}{2}$

Therefore, cos(480°) = -0.5

$\Rightarrow \sin(360^\circ+120^\circ)$

$\Rightarrow \sin(120^\circ)$ $\because \sin(360+\theta)=\sin\theta$

$\Rightarrow \sin(180^\circ-60^\circ)$ $\because 120=180-60$

$\Rightarrow \sin(60^\circ)$ $\because \sin(180-\theta)=\sin\theta$

$\Rightarrow \dfrac{\sqrt{3}}{2}$

Therefore, sin(480°) = 0.866

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3 years ago

The sum of three consecutive odd numbers is 177. What is the smallest of the three numbers?

lorasvet [3.4K]

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Consider the graph of the expotential function y= 3(2)^x

victus00 [196]

Answer:

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Step-by-step explanation:

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hasn't x-intercept

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if 0 < a < 1, then is decreasing

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Semmy [17]

Answer:

in 13.95 years the senior class will have 100 students.

Step-by-step explanation:

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