8 + 0.3 =
Standard . . . 8.3
Words . . . "eight and three tenths".
To find a scale factor between two similar figures, find two corresponding sides and write the ratio of the two sides. If you begin with the smaller figure, your scale factor will be less than one. If you begin with the larger figure, your scale factor will be greater than one.
The solutions of the equations are x = 1 and y = 2
The system of equations are
4x + 3y = 10
-4x + 5y = 6
Here we have to use the elimination method. Eliminate the x term and find the value of y term
Add both equation
3y + 5y = 10 +6
Add the like terms
8y = 16
y = 16 / 8
Divide the terms
y = 2
Substitute the value of x in the first equation
4x + 3y = 10
4x + 3×2 = 10
Multiply the terms
4x + 6 = 10
4x = 10 - 6
4x = 4
x = 4 / 4
Divide the terms
x = 1
Hence, the solutions of the equations are x = 1 and y = 2
Learn more about elimination method here
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Answer:
6
General Formulas and Concepts:
<u>Algebra I</u>
- Terms/Coefficients/Degrees
Step-by-step explanation:
<u>Step 1: Define</u>
9b⁶c⁵
<u>Step 2 Identify</u>
Our largest degree is the variable raised to the highest exponent.
b⁶ > c⁵
Therefore our degree is 6.
Perpendicular lines have slopes that multiply to get -1
y=mx+b is the slope intercept equation
m=slope
so get into y=mx+b form
-x+2y=4
solve for y
add x both sides
2y=x+4
divide by 2 both sides
y=(1/2)x+2
the slope is 1/2
perppendicular line slope multiplies to -1
1/2 times what=-1
times 2/1 both sides
what=-2/1=-2
y=-2x+b
find b
we are given a point is (-2,1)
when x=-2, y=1
1=-2(-2)+b
1=4+b
minus 3 both sides
-3=b
so the equation is
y=-2x-3
your teacher might want it in standard form (ax+by=c) so
add 2x both sides
2x+y=-3 is an equation
so y=-2x-3 is correct (slope intercept form)
2x+y=-3 is also correct (standard form)
