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3 years ago

I really need help on these two questions

Mathematics

1 answer:

Yuri [45]3 years ago

3 0

$(4^\frac{1}{3} )^3$ =4
$(6^ \frac{1}{6} )^6$ =6
$(3^ \frac{1}{2} )^4$ =
multiply $\frac{1}{2}$ by 4
and then simplify
$3^{2}$

so it will be
4x6x9=216
your answer is d.216

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The school cafeteria sells 300 half-pints Of milk everyday. How many gallons of milk is that?

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3 years ago

Four students took an exam the fraction of the total possible points that each received is given which students had the highest

Fittoniya [83]

Answer:

4% out of 100

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4% out of 100 students took the exam

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3 years ago

sashaice [31]

Answer:

Step-by-step explanation:

If slope of two lines are equal, then they are parallel lines.

If product of the slope of two lines is (-1), then they are perpendicular lines.

C) y = x + 2

Slope m1 = 1

y = -x + 3

Slope m2 = -1

m1 * m2 = 1 * (-1) = -1

These are perpendicular lines.

D) y = 3x + 2

Slope = m1 = 3

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Slopes are equal. So, they are parallel lines.

E)y= 3

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x = 4

This line is parallel to y-axis.

So, both lines are perpendicular to each other.

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8 0

2 years ago

Please hepl???<br>I will mark brainliest

zepelin [54]

Answer:

x = 59

Step-by-step explanation:

180 = 73 + x + (x-11)

180 - 73 + 11 = 2x

118 = 2x

x = 118/2

x = 59

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%20%5Crm%5Csum_%7Bn%20%3D%201%7D%5E%20%5Cinfty%20%28%20-%201%20%7B%29%7D%5E%7Bn%20-%201%7D%

victus00 [196]

Let

$\displaystyle f(x) = \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n-1}}{(2n-1)! (2n+1)}$

The exponent is indeed $2n-1$ - not a typo!

Take the antiderivative of $f$ , denoted by $F$ . This recovers a factor of $2n$ in the denominator, which lets us condense it to a single factorial.

$\displaystyle F(x) = \int f(x) \, dx = C + \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n}}{(2n+1)!}$

Recall the series expansion of sine,

$\displaystyle \sin(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n+1}}{(2n+1)!}$

Then with a little algebraic manipulation, we get

$\displaystyle F(x) = \int f(x) \, dx = C + 1 - \frac{\sin(x)}x$

Differentiate to recover $f$ .

$f(x) = \dfrac{\sin(x) - x\cos(x)}{x^2}$

Finally, $f(\pi) = \frac1\pi$ , so our sum is

$\displaystyle \pi^2 f(\pi) = \sum_{n=1}^\infty (-1)^{n-1} \frac{\pi^{2n+1}}{(2n-1)! (2n+1)} = \boxed{\pi}$

3 0

1 year ago