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Fittoniya [83]
3 years ago
8

Malachi is shopping for toothbrushes. He can buy a package of 2 for $3.48 or a package of 4 for $6.60. Which is a better buy?

Mathematics
2 answers:
Maurinko [17]3 years ago
8 0
Well if we multiply 3.48 times two which would make 4 toothbrushes it would be 6.96. So this means if we wanted a better deal on more toothbrushes. The answer would be the package of 4
kramer3 years ago
5 0
3.48x2= 6.96. Therefore if you bought the pack of 4 toothbrushes it would be a better deal bc you can get the same amount of toothbrushes for less since the 4 pack is 6.60 =)
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What is the sum of the first five terms of the geometric sequence in which a1=10 and r=1/2?
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(10(1-(1/2)^5)/1-(1/2) = 

20(1-1/32)
=155/8
5 0
3 years ago
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Jim buys a car for $22,500. He decides to finance through the dealership at 3.5% simple interest for 5.5 years. How much interes
borishaifa [10]

Answer:

4,331.25 in interest

Step-by-step explanation:

22,500.00x3.5%=787.50x5.5=4,331.25

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7 0
3 years ago
A tree grows the same amount each year.one year the tree is 48 inches tall.When it is measured 3 years later it is 84 inches.How
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8 0
3 years ago
Find the percent of markup. 37.00 to 49.00
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6 0
3 years ago
Read 2 more answers
Consider independent simple random samples that are taken to test the difference between the means of two populations. The varia
Arturiano [62]

Answer:

d. t distribution with df = 80

Step-by-step explanation:

Assuming this problem:

Consider independent simple random samples that are taken to test the difference between the means of two populations. The variances of the populations are unknown, but are assumed to be equal. The sample sizes of each population are n1 = 37 and n2 = 45. The appropriate distribution to use is the:

a. t distribution with df = 82.

b. t distribution with df = 81.

c. t distribution with df = 41.

d. t distribution with df = 80

Solution to the problem

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

This last one is an unbiased estimator of the common variance \sigma^2

So on this case the degrees of freedom are given by:

df= 37+45-2=80

And the best answer is:

d. t distribution with df = 80

5 0
3 years ago
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