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Crazy boy [7]
2 years ago
13

Someone please answer this, I would really be appreciative.

Mathematics
1 answer:
Iteru [2.4K]2 years ago
3 0

Answer:

y-30 = 3(x-1)

Step-by-step explanation:

Point-slope form of an equation is

y-y1 = m(x-x1)  where (x1,y1 ) is a point and m is the slope

We know on day 1 they exercised 30 minutes (1,30) where x is the number of days and y is the minutes.  The rate increased 3 minutes each day so m = 3

y-30 = 3(x-1)

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Which choice below is a common multiple of 8 and 10 (but not the least common multiple).
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3 years ago
A sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters. Give a point est
xxTIMURxx [149]

Answer:

Point estimate for the population variance = 3.92 * 10^{-3} .

Step-by-step explanation:

We are given that a sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters ;

       X                       X - Xbar                                         (X-Xbar)^{2}

      1.13            1.13 - 1.188 = -0.058                                 3.364 * 10^{-3}

      1.15            1.15 - 1.188 = -0.038                                 1.444 * 10^{-3}    

      1.15            1.15 - 1.188 = -0.038                                 1.444 * 10^{-3}

      1.24           1.24 - 1.188 = 0.052                                 2.704 * 10^{-3}

      1.27           1.27 - 1.188 = 0.082                               <u>  6.724 * </u>10^{-3}<u>    </u>

                                                                    \sum (X-Xbar)^{2} <u>= 0.01568   </u>

Firstly, Mean of above data, Xbar = \frac{\sum X}{n} = \frac{1.15+1.24+1.15+1.27+1.13}{5} = 1.188

Point estimate of Population Variance = Sample variance

                                                               = \frac{\sum (X-Xbar)^{2}}{n-1} = \frac{0.01568}{4} = 3.92 * 10^{-3} .

Therefore, point estimate for the population variance = 3.92 * 10^{-3} .

       

5 0
3 years ago
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