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NeTakaya
3 years ago
13

357,335 rounded to the nearest ten357,335 rounded to the nearest ten

Mathematics
1 answer:
Advocard [28]3 years ago
5 0

Answer:

357,340

Step-by-step explanation:

Locate the tens place:

357,3<u>3</u>5

Check the number to the right:

357,33<u>5 </u>

<u></u>

If the number is greater than or equal to 5, then we round up. If the number is less than or equal to 4, we round down.

The number next to the tens place is a '5'. We round up.

357,335 ≈ 357,340

Hope this helps.

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0.92 you would simply divide 23 by 25
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Help plz this is multiple choice so just choose the answer u think is correct.
babymother [125]

the answer is 34.83 I believe

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Lucy will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $53 and costs an add
Alchen [17]

Answer:

The amount driven would be 275, and the cost for both plans will be 77.75$

Step-by-step explanation:

make both equations

y=0.09x+53

y=0.13x+42

set them equal to each other and solve for x to get the distance

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6 0
2 years ago
(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x

2Ax + 2B = -8x

By inspection,

2B = 0 => B = 0

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x

(c) y'' + 2y = −8x + 14

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x + 7

(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

8 0
3 years ago
What is 45 + 97 + 140
sweet [91]

Answer:

Use a Calculator

Step-by-step explanation:

You have on on you phone

6 0
3 years ago
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