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Romashka [77]
2 years ago
13

Divide es001-1. Jpg the quotient is es001-2. Jpg the remainder is es001-3. Jpg es001-4. Jpg.

SAT
1 answer:
Naddika [18.5K]2 years ago
7 0

Answer:

10

x

4

−

14

x

3

−

10

x

2

+

6

x

−

10

=

(

x

3

−

3

x

2

+

x

−

2

)

(

10

x

+

16

)

+

28

x

2

+

10

x

+

22

Explanation:

                                                                          Quotient

↓

x

3

−

3

x

2

+

x

−

2

)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

10

x

4

−

14

x

3

−

10

x

2

+

6

x

−

10

(

10

x

+

16

                           

10

x

4

−

30

x

3

+

10

x

2

−

20

x

−−−−−−−−−−−−−−−−−−−−−−−

⏐

⏐

⏐

↓

                                       

16

x

3

−

20

x

2

+

26

x

−

10

                                       

16

x

3

−

48

x

2

+

16

x

−

32

−−−−−−−−−−−−−−−−−−−−−

Remainder      

→

                   

28

x

2

+

10

x

+

22

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Hence, quotient is

10

x

+

16

, remainder is

28

x

2

+

10

x

+

22

and

10

x

4

−

14

x

3

−

10

x

2

+

6

x

−

10

=

(

x

3

−

3

x

2

+

x

−

2

)

(

10

x

+

16

)

+

28

x

2

+

10

x

+

22

Explanation:

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Answer:

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Explanation:

Let be u = 6 + i\,2 and v = 3 + i\,5, the sum of the complex number can be found by algebraic means. That is:

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The periodic table is arranged by various patterns. Is there a pattern with regard to ionic charge? In three to five sentences,
Flura [38]

Ionic charge increases from left to right in periodic table which results in a decrease in ionic radius.

Ionic charge is the electrical charge of an ion formed when when an atom gains or losses electron.

Metals form ionic charge (cation) by the loss of electron while non-metal form ionic charge (anion) by the gain of electron.

  • This ionic charge increases across the group and consequently, results in a decrease of ionic radius.
  • When a positive ion (cation) transfers electron to the negative ion (anion) an Ionic bond will be formed.

<u>For example</u>;

  • ionic charge of group 1 elements = +1
  • ionic charge of group 2 elements = + 2
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Thus, we can conclude that ionic charge increases from left to right in periodic table which results in a decrease in ionic radius.

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