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3 years ago

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Out of 120 students in exam, 2/3 of them passed. How many students passed?

2 answers:

LenKa [72]3 years ago

8 0

Out of 120 students in exam, 2/3 of them passed. How many students passed?

now,

no of students passed = 2/3×120

= 0.66×120

=80...

therefore <em>8</em><em>0</em><em> </em><em> </em><em>students</em><em> </em><em>were</em><em> </em><em>passed</em><em>.</em><em>.</em><em>.</em><em>.</em>

Alex Ar [27]3 years ago

8 0

Answer:

80

Step-by-step explanation:

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What is the algebraic expression for: four less than three times the number of egg orders and six more than two times the number

Ira Lisetskai [31]

3n - 4 + 6 + 2n

I believe that's the answer!

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3 years ago

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

So

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

So

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

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3 years ago

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3 years ago

Two consecutive integers whose sum is -31

Gnesinka [82]

Answer:

- 15, - 16

Step-by-step explanation:

-15 + (-16) = - 15 - 16 = - 31

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3 years ago

Read 2 more answers

Find the 23rd term of this sequence -25,-15,-5,5....

notsponge [240]

Answer:

195

Step-by-step explanation:

To find the 23rd term of this sequence, we can use the arithmetic sequence formula $a_{n} =a_{1} +(n-1)d$ where,

$a_{n}$ = $n^{th}$ term

$a_{1}$ = first term

$n$ = term position

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3 years ago