K = ln (153/147)/7
k =
<span>
ln
(<span>
<span>
1.0408163265)/7
k = </span></span></span>0.040005334584
y(t) = a * e ^ k*t
y(2017) = 147 * e^ <span><span><span>0.040005334584
</span>
</span>
</span>
* 26
y(2017) = 147*e^
<span>
<span>
<span>
1.0401386992
</span>
</span>
</span>
y(2017) = 147*
<span>
<span>
<span>
2.8296094512
</span>
</span>
</span>
<span>y(2017) = 415.95 NOT very sure of that answer
</span>
Answer:
Initial Value=15
Rate of change=15/10=1.5
Equation: y=1.5x+15
Step-by-step explanation:
y=ax+b
y=1.5x+b
15=1.5(0)+b
b=15
Answer:
<h2>-33x - 82</h2>
Step-by-step explanation:
Use
PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
and the distributive property a(b + c) = ab + ac.
![1)\qquad5(x+3)=5x+15\\\\2)\qquad x+5(x+3)=x+5x+15=6x+15\\\\3)\qquad2[x+5(x+3)]=2(6x+15)=12x+30\\\\4)\qquad x-2[x+5(x+3)]=x-(12x+30)=x-12x-30=-11x-30\\\\5)\qquad3\{x-2[x+5(x+3)]\}=3(-11x-30)=-33x-90\\\\6)\qquad8+3\{x-2[x+5(x+3)]\}=8+(-33x-90)=-33x-82](https://tex.z-dn.net/?f=1%29%5Cqquad5%28x%2B3%29%3D5x%2B15%5C%5C%5C%5C2%29%5Cqquad%20x%2B5%28x%2B3%29%3Dx%2B5x%2B15%3D6x%2B15%5C%5C%5C%5C3%29%5Cqquad2%5Bx%2B5%28x%2B3%29%5D%3D2%286x%2B15%29%3D12x%2B30%5C%5C%5C%5C4%29%5Cqquad%20x-2%5Bx%2B5%28x%2B3%29%5D%3Dx-%2812x%2B30%29%3Dx-12x-30%3D-11x-30%5C%5C%5C%5C5%29%5Cqquad3%5C%7Bx-2%5Bx%2B5%28x%2B3%29%5D%5C%7D%3D3%28-11x-30%29%3D-33x-90%5C%5C%5C%5C6%29%5Cqquad8%2B3%5C%7Bx-2%5Bx%2B5%28x%2B3%29%5D%5C%7D%3D8%2B%28-33x-90%29%3D-33x-82)
Solution
Question 1:
- Use of the area of squares to explain the Pythagoras theorem is given below
- The 3 squares given above have dimensions: a, b, and c.
- The areas of the squares are given by:

- The Pythagoras theorem states that:
"The sum of the areas of the smaller squares add up to the area of the biggest square"
Thus, we have:

Question 2:
- We can apply the theorem as follows:
![\begin{gathered} 10^2+24^2=c^2 \\ 100+576=c^2 \\ 676=c^2 \\ \text{Take square root of both sides} \\ \\ c=\sqrt[]{676} \\ c=26 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2010%5E2%2B24%5E2%3Dc%5E2%20%5C%5C%20100%2B576%3Dc%5E2%20%5C%5C%20676%3Dc%5E2%20%5C%5C%20%5Ctext%7BTake%20square%20root%20of%20both%20sides%7D%20%5C%5C%20%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B676%7D%20%5C%5C%20c%3D26%20%5Cend%7Bgathered%7D)
Thus, the value of c is 26
Where is the rest of the question??