Price of gallon of gasoline one year ago is $ 4.1
<em><u>Solution:</u></em>
Given that you pay $ 3.69 for a gallon of gasoline
This is 90% of the price of a gallon of gasoline one year ago
To find: price of a gallon of gasoline one year ago
We can solve this sum by setting up proportion
Let "x" be the price of gallon of gasoline once year ago
By proportions we get,
Thus price of gallon of gasoline one year ago is $ 4.1
Method 2:
you pay $ 3.69 for a gallon of gasoline
Let "x" be the price of gallon of gasoline once year ago
3.69 = 90% of the price of a gallon of gasoline one year ago
3.69 = 90 % of x
Thus price of gallon of gasoline one year ago is $ 4.1
answer :
is equals to 2 Kama Q is equals to 3 Kama P is equal to minus Q is equals to 9 Pharma fees equals to minus 25 Q is equals to 6 = 2 - 61
step by step explainaion:2 by 3 Kama minus 5 by 9 Kama minus 25 by 6 - 61 by to all rational
You can draw 15 lines and 7 lines as inches and add them all together.
15+7=22
<u><em>Answer:</em></u>
<u><em>Here's the answer:</em></u>
<u><em>r = √ ( x2 + y2 )</em></u>
Answer:
Step-by-step explanation:
The sum of two even numbers is an even number