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3 years ago

find the slope-intercept form of the line whose slope os 4 and that passes through the point (-9,12)

Mathematics

1 answer:

Trava [24]3 years ago

7 0

Answer:

y = 4x+48

Step-by-step explanation:

Slope intercept form is y=mx+b. We already know the value for m(4), so we can plug in the x and y coordinates for x and y in the equation. This gives us 12=4(-9)+b. Solve for b to get 48

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egoroff_w [7]

Answer:

205 : 41

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3 years ago

Read 2 more answers

What is the area of this figure? <br>

polet [3.4K]

First, calculate the area of the square, which is 25

next, find the area of one half of the triangle by multiplying 2.5 and 4 (10), then dividing that by 2 (5).

since the two half’s of the triangle are symmetrical, just add 5 and 5 to get 10.

add the area of the triangle (10) and the square (25) to get the total area.

the answer should be 35

hope this helps!

4 0

1 year ago

Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo

natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

P(B) is the probability of the person having cancer, so $P(B) = 0.009$

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So $P(A/B) = 0.91$

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

$P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765$

What is the probability that the person actually does have cancer?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213$

There is a 12.13% probability that the person actually does have cancer.

3 0

2 years ago

According to a certain country's department of education, 39.9% of 3-year-olds are enrolled in day care. what is the probabi

Yuliya22 [10]

The probability would be 39.9%

The given probability states that 39.9% of the 3 years olds are in daycare. Therefore, it would be obvious to assume that if you randomly selected a 3 year old, that would be the probability that he/she is in daycare.

8 0

3 years ago

Find the average rate of change over the given interval <br> f(x) = 2^x , [3,5]

Vlada [557]

Answer:

$y=x*2^x (3,5)+y$

Step-by-step explanation:

4 0

2 years ago

find the slope-intercept form of the line whose slope os 4 and that passes through the point (-9,12)​

find the slope-intercept form of the line whose slope os 4 and that passes through the point (-9,12)