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Vikki [24]
2 years ago
15

I need help on this 8th grade math this is due tomorrow.

Mathematics
1 answer:
LekaFEV [45]2 years ago
6 0

Answer:

<h2>u²=6.25</h2><h2>p²=5</h2>

Step-by-step explanation:

Raise 2.5 to the power of 2 =

6.25

Pull terms out from under the radical, assuming positive real numbers =

5

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Can anyone do this thanks
vovangra [49]
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2) sept.
4) aug. &' sept
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4 0
2 years ago
A candy bar box is in the shape of a triangular prism. The volume of the box is 3,240 cubic centimeters.
SashulF [63]
<span>B: To make the box, we need 2 triangular ends,

and 3 rectangular sides. Side the volume = 3240

and the height = 30, the area of each base (end) = 108.

The sides have areas of 30 x 42 = 720, and 30 x 15 = 450,

and there are 2 of those. So total area = 108 + 108 + 720 + 900 = 1836 cm^2
 
creds to yahoo answer

</span>
8 0
2 years ago
Solve the following 3 × 3 system. Enter the coordinates of the solution below.
love history [14]
The system is:

i)    <span>2x – 3y – 2z = 4
ii)    </span><span>x + 3y + 2z = –7
</span>iii)   <span>–4x – 4y – 2z = 10 

the last equation can be simplified, by dividing by -2, 

thus we have:

</span>i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7
iii)   2x +2y +z = -5 


The procedure to solve the system is as follows:

first use any pairs of 2 equations (for example i and ii, i and iii) and equalize them by using one of the variables:

i)    2x – 3y – 2z = 4   
iii)   2x +2y +z = -5 

2x can be written as 3y+2z+4 from the first equation, and -2y-z-5 from the third equation.

Equalize:  

3y+2z+4=-2y-z-5, group common terms:
5y+3z=-9   

similarly, using i and ii, eliminate x:

i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7

multiply the second equation by 2:


i)    2x – 3y – 2z = 4
ii)    2x + 6y + 4z = –14

thus 2x=3y+2z+4 from i and 2x=-6y-4z-14 from ii:

3y+2z+4=-6y-4z-14
9y+6z=-18

So we get 2 equations with variables y and z:

a)   5y+3z=-9 
b)   9y+6z=-18

now the aim of the method is clear: We eliminate one of the variables, creating a system of 2 linear equations with 2 variables, which we can solve by any of the standard methods.

Let's use elimination method, multiply the equation a by -2:

a)   -10y-6z=18 
b)   9y+6z=-18
------------------------    add the equations:

-10y+9y-6z+6z=18-18
-y=0
y=0,

thus :
9y+6z=-18 
0+6z=-18
z=-3

Finally to find x, use any of the equations i, ii or iii:

<span>2x – 3y – 2z = 4 
</span>
<span>2x – 3*0 – 2(-3) = 4

2x+6=4

2x=-2

x=-1

Solution: (x, y, z) = (-1, 0, -3 ) 


Remark: it is always a good attitude to check the answer, because often calculations mistakes can be made:

check by substituting x=-1, y=0, z=-3 in each of the 3 equations and see that for these numbers the equalities hold.</span>
3 0
2 years ago
Read 2 more answers
Who prescribed the most medicine and why explain
Veronika [31]
The answer is either Dr Tanenbaum or Dr hong.<span />
6 0
3 years ago
When c=3 and d=7<br> 21c + 2d - |-11|d
NeX [460]

Answer:

0

Step-by-step explanation:

21(3) +2(7) - 11(7)             because the absolute value of -11 is 11

63+14-77

=0

8 0
3 years ago
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