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professor190 [17]
3 years ago
11

172+(-167)+(-10)+(-144) what's the sum

Mathematics
1 answer:
Pepsi [2]3 years ago
6 0
-149 would be your answer
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6²•8² = [?]<br>Enter the value that goes in the box​
Damm [24]

Answer:

36 * 64

= 2304

Hope it help

3 0
3 years ago
Can someone please help me!!!!!!!!
masya89 [10]

Answer:

√69 is 8.30 and √72 is 8.48.

The one after N should be 8.50.

So really it should be N, not M, im sorry. Because M is 8.20

So its N

Step-by-step explanation:

I hope this helps    :)

7 0
3 years ago
Write the sentence as an equation. Then solve 2 less than one-sixth of a number n is 5
lakkis [162]

Answer:

n=42

Step-by-step explanation:

n/6-2=5

n/6=7

n=42

5 0
3 years ago
Assignment: Using Prime Factorization Investigation
damaskus [11]

Answer:

  1. 3(2 +7)
  2. 9(3 +5)
  3. 16(2 +3)
  4. 15(2 +5)
  5. 8(11 +3)

Step-by-step explanation:

  1. 6 + 21 = 2·3 + 3·7 = 3(2 +7)
  2. 27 + 45 = 3^3 + 3^2·5 = 9(3 +5)
  3. 32 + 48 = 2^5 + 2^4·3 = 16(2 +3)
  4. 30 + 75 = 2·3·5 + 3·5^2 = 15(2 +5)
  5. 88 + 24 = 2^3·11 +2^3·3 = 8(11 +3)

In each case, the factor outside parentheses is the greatest common factor, the product of the prime factors common to both numbers. When the same factor has different powers, the least power is the common factor.

3 0
3 years ago
Every day, a comes to the bus stop at the same time, and boards the first bus that arrives. the arrival of the first bus is an e
mylen [45]
So the waiting time for a bus has density f(t)=λe−λtf(t)=λe−λt, where λλ is the rate. To understand the rate, you know that f(t)dtf(t)dt is a probability, so λλ has units of 1/[t]1/[t]. Thus if your bus arrives rr times per hour, the rate would be λ=rλ=r. Since the expectation of an exponential distribution is 1/λ1/λ, the higher your rate, the quicker you'll see a bus, which makes sense.

So define <span><span>X=min(<span>B1</span>,<span>B2</span>)</span><span>X=min(<span>B1</span>,<span>B2</span>)</span></span>, where <span><span>B1</span><span>B1</span></span> is exponential with rate <span>33</span> and <span><span>B2</span><span>B2</span></span> has rate <span>44</span>. It's easy to show the minimum of two independent exponentials is another exponential with rate <span><span><span>λ1</span>+<span>λ2</span></span><span><span>λ1</span>+<span>λ2</span></span></span>. So you want:

<span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span></span>

where <span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span></span>.

8 0
3 years ago
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