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2 years ago

172+(-167)+(-10)+(-144) what's the sum

Mathematics

1 answer:

Pepsi [2]2 years ago

6 0

-149 would be your answer

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What is the surface area of the square pyramid?

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sa (surface area) = $a^{2} + 2a$ $\sqrt{x} \frac{a^2}{4} + h^2\\$

Step-by-step explanation:

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2 years ago

Larinda cooked a 4-kilogram roast. The roast left over after the meal weighed 3 kilograms. How many grams of roast were eaten du

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1 kilogram was eaten

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3 years ago

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2 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

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2 years ago

Many fundraisers ask for donations using email and text messages. A paper describes an experiment to investigate whether the pro

blagie [28]

Answer:

b. donations using text message

d. donations using email

Step-by-step explanation:

From the question, it is clear that the people who received these requests were assigned to two groups and these 2 were assigned treatments of if they make donations after either receiving email or text messages after which their respective proportions p1 and p2 are determined.

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2 years ago