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lions [1.4K]
4 years ago
9

A new car is purchased for 23700 dollars.the value o the car depreciates at 13.5% per year what will be the value of the car be,

to the nearest cent,after 10 years
Mathematics
2 answers:
lara31 [8.8K]4 years ago
5 0

it will be 31,995 but we have to estimate yo the nearest cent so 10 cents

melamori03 [73]4 years ago
4 0

Answer:

Step-by-step explanation:

let the price of the car be $ 23 700

The depreciation will be 13.5 % per year

Thus, the car will depreciate at a rate of :

\frac{13.5}{100} * 23700\\ = 3199.5

After 10 years, the car will be: = $  23 700 - (10× $ 3199.50)

                                                  = - $ 4 695

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Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

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Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, xy \leq 8000

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220x-x^2 \leq 8000

So,220x-x^2 = 8000\\-x^2+220x-8000=0

General quadratic equation : ax^2+bx+c=0

Formula : x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0
3 years ago
A box contains a $1 bill, a $5 bill, a $10 bill, and a $20 bill. If two bills are selected at random what is the probability tha
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Answer:

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Answer:

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