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baherus [9]
3 years ago
15

Edward was running errands on his bike first to be like from his house to the post office to pick up a package the post office i

s 4 4/5 miles away from his house next Edward bike to the market for a cold drink the market is 3.25 miles from the post office his mother picked him up at the market and drove him home how many miles did Edward back altogether
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

Answer:

Edward drove altogether of 16.1 miles.

Step-by-step explanation:

Given:

Edward was Running around on his bike.

Distance from home to post office = 4 \frac{4}{5} \ miles

4 \frac{4}{5} \ miles can be Rewritten as 4.8 \ miles

Distance from home to post office = 4.8 \ miles

Now Given:

Distance from Post office to market = 3.25 miles.

Now we will calculate Distance from Home to market.

Distance from Home to market can be calculated by adding Distance from home to post office and Distance from Post office to market.

Framing in equation form we get;

Distance from Home to market = 4.8+3.25 = 8.05\ miles

Also Given:

his mother picked him up at the market and drove him home.

We need to find the total miles Edward drive altogether.

total miles Edward drive altogether will be equal to Sum of Distance from Home to market and Distance from market to home.

framing in equation form we get;

Total Distance Edward drove = 8.05+8.05 = 16.1\ miles

Hence Edward drove altogether of 16.1 miles.

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Answer: A) Option B

B) 22.3 minutes.

Step-by-step explanation:

The temperature decreases in an exponential decrease, this means that we can write the equation as:

T(x) = A*r^x + B

Where A is the difference between the initial temperature and the room temperature, B is the room temperature, and r is a positive number smaller than 1, that says "how fast" the temperature decreases (and x is the variable, in units of time)

We know that the initial temperature

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The only option with those two values is option B.

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We should check that when x = 2m, the temperature must be 197°

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So this equation is correct

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