9514 1404 393
Answer:
a) P(t) = 6.29e^(0.0241t)
b) P(6) ≈ 7.3 million
c) 10 years
d) 28.8 years
Step-by-step explanation:
a) You have written the equation.
P(t) = 6.29·e^(0.0241·t)
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b) 2018 is 6 years after 2012.
P(6) = 6.29·e^(0.0241·6) ≈ 7.2686 ≈ 7.3 . . . million
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c) We want t for ...
8 = 6.29·e^(0.0241t)
ln(8/6.29) = 0.0241t
t = ln(8/6.29)/0.0241 ≈ 9.978 ≈ 10.0 . . . years
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d) Along the same lines as the calculation in part (c), doubling time is ...
t = ln(2)/0.0241 ≈ 28.7613 ≈ 28.8 . . . years
A <em>bisector</em> is a line that divides either a given line or an angle into <u>two</u> equal parts. The <em>answer </em>to the given question is in the <u>attachments</u> to this answer.
The process of <u>bisection</u> implies dividing a given angle or line into<em> two</em> equal parts. Thus a bisector should be constructed.
The <u>construction</u> required is as given below:
For figure 1:
- With <em>center</em> S and any radius, draw an arc to<u> intersect</u> S and T.
- Using the <u>end</u> of the arc on SR and a greater radius, draw two arcs.
- Using the <em>end</em> of the arc on ST and the same radius, draw another arc to <em>intersect</em> the previous arc.
- Join S to the point of <em>intersection</em> of the arcs by a straight line. Thus this line is the required <u>bisector</u> of <RST.
For figure 2:
- With <em>center</em> u and any radius, draw an arc to <u>intersect</u> T and V.
- Using the end of the arc on uT and a greater radius, draw two arcs.
- Using the end of the arc on uV and the same radius, draw another arc to intersect the previous arc.
- Join u to the point of<u> intersection </u>of the arcs by a straight line. Thus this line is the required<em> bisector</em> of <TuV.
For figure 3:
- With center B and any radius, draw an arc to <em>intersect</em> A and C.
- Using the end of the arc on AB and a greater radius, draw two arcs.
- Using the end of the arc on BC and the same radius, draw another arc to<u> intersect</u> the previous arc.
- Join B to the point of<em> intersection</em> of the arcs by a straight line. Thus this line is the required<u> bisector</u> of <ABC.
The required construction is as shown in the <u>attachments</u> to this answer.
For more clarifications on bisection of angles, visit: brainly.com/question/12028523
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Answer:
581 square centimeters
Step-by-step explanation:
Ahh I’m not smart so imma just guess not saying it’s right . 24 in?