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viktelen [127]
2 years ago
6

There is a special relationship between the lengths of the legs of a right triangle and the length of its hypotenuse. This relat

ionship is known as the
Mathematics
2 answers:
ExtremeBDS [4]2 years ago
4 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The special relationship between the hypotenuse and the other two sides of a right angled Triangle is known as Pythagorean theorem.

According to the theorem :

(hypotenuse)² = (base)² + (perpendicular)²

sattari [20]2 years ago
3 0

Answer:

Hello, There!

<h2>Question</h2>

There is a special relationship between the lengths of the legs of a right triangle and the length of its hypotenuse. This relationship is known as the

<h2>Answer</h2>

Pythagorean Theorem.

Step-by-step explanation:

The Pythagorean Theorem states that the square of one leg (a) plus the square of the other leg (b) is equal to the square of the hypotenuse (c). This can be written as A^{2} + B^{2} = C^{2}.

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sukhopar [10]

Answer:

m = -18

Step-by-step explanation:

<u>Step 1:  Combine like terms</u>

-8 = -m + 2m + 10

-8 = m + 10

<u>Step 2:  Subtract 10 from both sides</u>

-8 - 10 = m + 10 - 10

-18 = m

Answer:  m = -18

6 0
3 years ago
What is the value of |−8.6|<br><br> a −8.6<br> b −1.4<br> c 1.4<br> d 8.6<br> thanks
nikklg [1K]

Hi!

When a number has lines on the outside of it like that, it means that it's the distance from 0. It's known as the absolute value.

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The answer is d 8.6

Hope this helps! :)

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3 years ago
Given that MQL =180° and XQR = 180°, which equation could be used to solve problems involving the relationships
Ganezh [65]

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Option A is the right answer.

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2 years ago
ANSWER IT CORRECTLY FOR BRAINLIEST Amelia built a scale model of a float, using the scale 48:7. The measurements of the actual f
Rashid [163]

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2 years ago
HELP PLEASE <br> solve the right triangle
aleksandrvk [35]

Answer:

Part 1) FG=4.4\ units

Part 2) EF=3.9\ units

Part 3) m\angle G=63^o

Step-by-step explanation:

step 1

Find the measure of length side FG

In the right triangle EFG

we know that

sin(27^o)=\frac{GE}{FG} ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

sin(27^o)=\frac{2}{FG}

FG=\frac{2}{sin(27^o)}=4.4\ units

step 2

Find the measure of length side EF

In the right triangle EFG

we know that

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substitute the given values

cos(27^o)=\frac{EF}{4.4}

EF=cos(27^o)(4.4)=3.9\ units

step 3

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we know that

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