Answer:
16.65$
Step-by-step explanation:
$20,000
25,000,000 x 0.0002 = 5,000
5,000 x $4.00= $20,000
Answer:
Mean = 2.7
In a group of 74090 we would expect about 3 (rounding to nearest whole number) children with the rare form of cancer.
Step-by-step explanation:
We are given that the rate of cancer in children is 37 children in 1 million. So the probability of cancer in a child is P(C) = 0.000037
Poisson distribution is used to approximate the number of cases of diseases and we have to find what will be the mean number of cases for 74,090.
In simple words we have to find the expected number of children with cancer in a group of 74,090 children.
The mean value of expected value can be obtained by multiplying the probability with the sample size. So, in this case multiplying probability of child having a cancer with total group size will give us the expected or mean number of children in the group with cancer.
Mean = E(x) = P(C) * Group size
Mean = 0.000037 x 74090
Mean = 2.7
This means in a group of 74090 we would expect about 3 (rounding to nearest whole number) children with the rare form of cancer.
Answer:
The value on the In side: 2
The first value on the Out side: 87
The second value on the Out side: 93
Step-by-step explanation:
First, I started by finding the differences by each step on both sides. I noticed that they increased together. 45-27 is 18, and it mirrored on the other side. 27-9 is 18, and it mirrored. By this I mean that 81-63=18 as well as 63-45=18. So I followed this pattern 45-38=7, so 9-7=2, and that gives us our first answer. 51-45=6, so 81+6=87, gives us our second. 57-51=6, so 87+6=93, and this gives us our third.
M=dc/dp=4/6=4/6=2/3
c(p)=2p/3 +b using (6,4)
4=2(6)/3+b
4=4+b, b=0 so
c(p)=2p/3
(the number of cherries needed as a function of the number of pies)
