3,162? I think it’s that I’m not sure.
Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Answer:
80
Step-by-step explanation:
89^2-39^2=6400, 6400=80^2
Answer:
x = 9
Step-by-step explanation:
The outer and inner triangles are similar, thus the ratios of corresponding sides are equal, that is
= 
, that is
= ( cross- multiply )
12(x - 3) = 8x
12x - 36 = 8x ( subtract 8x from both sides )
4x - 36 = 0 ( add 36 to both sides )
4x = 36 ( divide both sides by 4 )
x = 9
Answer:
largest 4 digit number × largest 3 digit number
=9999 × 999
(10000-1)×(1000-1) = (a-b)(c-b)= ac-ab-bc+b^2
10000000-10000-1000+1 = 9989001
