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boyakko [2]
3 years ago
5

MULTIPLE CHOICE QUESTION

Mathematics
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

Subtract 36 and 16

Step-by-step explanation:

16 + b^2 = 36

Subtract 16 from each side

16+b^2 -16 = 36-16

b^2 = 20

Take the square root of each side

sqrt(b^2) = sqrt(20)

b = sqrt(20)

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What is “8 - 4(-x + 5)” equivalent too?
RSB [31]

Answer:

4x -12

Step-by-step explanation:

8 - 4(-x + 5)

Distribute

8 -4(-x) -4(5)

8 +4x -20

4x -12

4 0
3 years ago
Read 2 more answers
At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent inecrease of water in th
Hitman42 [59]

Question:

At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent decrease of water in the tank

Answer:

The percent Decrease of water in the tank  is 50%

Step-by-step explanation:

Given:

Initial amount of water in the tank at the noon = 6 cm

amount of water remained in water after several hours = 3 cm

To Find:

The percent decrease =?

Solution:

The percent decrease in the tank

=>\frac{\text {water present after some hours }}{\text {initial water contained in the tank }} \times 100

Substituting the values

=>\frac{3}{6} \times 100

=>\frac{1}{2} \times 100

=>\frac{100}{2}

=> 50

5 0
3 years ago
In the diagram below, we have $ST = 2TR$ and $PQ = SR = 20$. Find the length $UV$.
Maslowich

Answer:

12

Step-by-step explanation:

1. ST=2TR and SR=20, then by segment addition postulate

ST+TR=SR\\ \\2TR+TR=SR\\ \\3TR=20\\ \\TR=\dfrac{20}{3}\\ \\ST=2\cdot \dfrac{20}{3}=\dfrac{40}{3}

2. Consider triangles PQU and TSU. These triangles are similar by AA similarity theorem (triangles have congruent vertical angles PUQ and TUS and congruent alternate interior angles PQU and TSU). Similar triangles have proportional corresponding sides, so

\dfrac{QU}{US}=\dfrac{PQ}{ST}=\dfrac{20}{\frac{40}{3}}=\dfrac{60}{40}=1.5

QU=1.5US

3. Consider triangles QUV and QSR. These triangles are similar by AA similarity theorem. Similar triangles have proportional corresponding sides, so

\dfrac{QU}{QS}=\dfrac{UV}{SR}\\ \\\dfrac{QU}{QU+US}=\dfrac{1.5US}{1.5US+US}=\dfrac{1.5}{2.5}=0.6

so

\dfrac{UV}{SR}=0.6\Rightarrow UV=0.6SR=0.6\cdot 20=12

7 0
3 years ago
Read 2 more answers
Rewrite f(x) = 3(x − 2)2 + 1 from vertex form to standard form.
Tom [10]

Answer:

f(x) = 9x^2-36x+37

Step-by-step explanation:

3(x-2)^2+1

(3x-6)^2+1

9x^2-36x+36+1

9x^2-36x+37

6 0
3 years ago
1,030 at 4% compounded semiannually for 2 years
kotegsom [21]

Answer: $1114.91

Step-by-step explanation:

The formula for compound interest is

A= P(1+\frac{r}{n})^{nt}  \\

Where

A = final amount

P = initial principal balance (1030 for this)

r = interest rate (0.04 for this)

n = number of times interest applied per time period (2 for this)

t = number of time periods elapsed (2 for this)

A= 1030(1+\frac{.04}{2})^{(2)(2)}  \\\\A= 1030(1+0.02)^{4} \\A=1030(1.02)^4\\A=1114.905125

This rounds up to $1114.91

6 0
3 years ago
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