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Kitty [74]
3 years ago
14

Como puedo ser digna con una persona y bondadosa

Physics
1 answer:
Firlakuza [10]3 years ago
8 0

Answer:

¿Es una pregunta de la escuela o de la vida?

Explanation:

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A satellite orbiting the earth is directly over a point on the equator at 12:00 midnight every three days. It is not over that p
victus00 [196]

Answer: the radius of the satellite's orbit  is  r = 8.78×10⁷m

Explanation:

given the time period, T= 3days

converting the time in days to seconds is given as;

time, T=(3*24*60*60) sec

T=259200 sec

from the force relation;

mv²/r = Gm×M/r²

v²=G×M/r ---------------(1)

and

V=2pi×r/T

V²=4×pi²×r²/T²

====>

from equation  (1) , we have

4×pi²×r²/T²=G×M/r

this becomes;  4×pi²×r³/T² = G×M

r³ = G×M×T²/(4pi²)

r³ = 6.67×10⁻¹¹×(5.97×10²⁴)×(259200)²/(4pi²)

==> r=8.78×10⁷m

radius of the orbit, r=8.78×10⁷ m

8 0
4 years ago
A spy satellite uses a telescope with a 1.7-m-diameter mirror. It orbits the earth at a height of 180 km.
WINSTONCH [101]

Answer: the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

Explanation:

Given that;

diameter of the mirror d = 1.7 m

height h = 180 km = 180 × 10³ m

wavelength λ = 500 nm = 5 × 10⁻⁹ m

Now Angular separation from the peak of the central maximum is expressed as;

sin∅= 1.22 λ / d

sin∅ = (1.22 × 5 × 10⁻⁹) / 1.7

 sin∅ = 3.588 × 10⁻⁷

we know that;

 sin∅  = object separation / distance from telescope

object separation =   sin∅ × distance from telescope

object separation = 3.588 × 10⁻⁷  × 180 × 10³

object separation =6.45 × 10⁻² m

then we convert to centimeter

object separation = 6.45 cm

Therefore the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

5 0
3 years ago
In order to have beef becomes tender she will use
jekas [21]

Answer:

you

Explanation:

you will be used is this frl?

8 0
2 years ago
Read 2 more answers
A pebble is dropped from rest from the top of a tall cliff and falls 53.4 m after 3.3 s has elapsed. How much farther does it dr
jeka94

Answer:

426.84 m

Explanation:

initial velocity u = 0

time t = 3.3 s

distance travelled s = 53.4 m

acceleration due to gravity = g

s = ut + 1/2 g t²

53.4 = 0 + 1/2 g x 3.3²

g = 9.8 m /s²

For the whole length of fall

distance travelled = h

total time = 6.6 + 3.3 = 9.9 s

h = ut + 1/2 g t²

u again = 0

h = .5 x 9.8 x 9.9²

= 480.24 m

distance travelled in last 6.6 s

= 480.24 - 53.4

= 426.84 m

6 0
3 years ago
How many minutes does light need to travel from the sun to Jupiter?
nydimaria [60]

Light travels at a speed of 299,792 kilometers per second; 186,287 miles per second

Mercury it will take 193.0 seconds(3.2 minutes)

Venus it will take 360.0 seconds(6.0 minutes)

Earth it will take 499.0 seconds(8.3 minutes)

Mars  It will take 759.9 seconds(12.6 minutes)

Jupiter  It will take 2595.0 seconds(43.2 minutes)

Saturn it will take 4759.0 seconds(79.3 minutes)

Uranus it will take 9575.0 seconds(159.6 minutes)

Neptune it will take 14998.0 seconds(4.1 hours)

Pluto  it will take 19680.0 seconds(5.5 hours)

3 0
3 years ago
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