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3 years ago

If 10 litres of paint cost £45 find the cost of 13litres

Mathematics

2 answers:

kobusy [5.1K]3 years ago

5 0

Answer:

58.5

Step-by-step explanation:

Divide 45 by 10. This is the cost of 1 liter. Then multiply by 13 and get the cost of 13 liters! Hope it helps! Good Luck!

gizmo_the_mogwai [7]3 years ago

5 0

Answer:

£58.50

Step-by-step explanation:

Ratio of Paint : Cost

10 : 45

13 : x

10x : 585

$\frac{10x}{10} = \frac{585}{10} \\ x = 58.5$

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He will have 56 cards left. Hope it help!

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3 years ago

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A coffee shop spends $408 for an order of 17 cases of paper cups. If the coffee shop adds 5 more cases of paper cups to the orde

-Dominant- [34]

Answer:

$528

Step-by-step explanation:

If cost is proportional to order quantity, the cost for 17+5 = 22 cases of cups will be 22/17 times the cost for 17 cases:

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4 years ago

Solve the equation -x=2-3x+3 and show your work/step by step

Debora [2.8K]

Answer:

x = $\frac{5}{2}$

Decimal Form: 2.5

Step-by-step explanation:

1) First, you have to simplify 2 − 3x + 3 to −3x + 5.

−x = −3x + 5

2) Next, You add 3x to both sides.

−x + 3x = 5

3) Then, Simplify −x + 3x to 2x.

2x = 5

4) Lastly, you divide both sides by 2 and you're done!

x = $\frac{5}{2}$

Decimal Form: 2.5

4 0

4 years ago

Find the differential of each function. (a) y = tan( 5t ) dy = Correct: Your answer is correct. (b) y = 5 − v2 5 + v2

Trava [24]

Answer:

$(a)$ $dy = 5sec^2(5t) \ dt$

$(a) \ dy = \frac{-20v}{(5+v^2)^2} \ dt$

Step-by-step explanation:

Given;

(a) y = tan(5t)

$(b) \ y = \frac{5-v^2}{5+v^2}$

Solving for (a)

y = tan(5t)

let u = 5t

⇒y = tan(u)

du/dt = 5

dy/du = sec²u

$\frac{dy}{dt} =\frac{dy}{du} *\frac{du}{dt} \\\\\frac{dy}{dt} = sec^2(u)*5\\\\\frac{dy}{dt} = 5sec^2(u)\\\\\frac{dy}{dt} = 5sec^2(5t)$

$dy = 5sec^2(5t) \ dt$

Solving for b;

let u = 5 - v²

du/dv = -2v

let v = 5+ v²

dv/du = 2v

$\frac{dy}{dv} = \frac{vdu - udv}{v^2} \\\\\frac{dy}{dv} = \frac{-2v(5+v^2) - 2v(5-v^2)}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-10v-2v^3-10v+2v^3}{(5+v^2)^2}\\\\$

$\frac{dy}{dv} = \frac{-10v-10v}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-20v}{(5+v^2)^2}\\\\dy = \frac{-20v}{(5+v^2)^2} dt$

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3 years ago

Alberto bought his bicycle for$275. He sold for $350. What was the amount of his Percentage profit?

juin [17]

Answer:

Step-by-step explanation:

$350 -$275= $75 profit

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3 years ago