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2 years ago

How to place 5/3 on a number line

Mathematics

2 answers:

finlep [7]2 years ago

7 0

Answer:

Step-by-step explanation:

Convert improper fraction to mixed fraction.

$\dfrac{5}{3}=1\dfrac{2}{3}$

1 2/3 is between 1 and 2. denominator is three. Divide into 3 parts.

german2 years ago

5 0

Step-by-step explanation:

the answer is in the image above

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3 years ago

Find the perimeter and are of the trapezoid

lara31 [8.8K]

Answer:

47.7ft

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2 years ago

Find the equation of the line specified. The line passes through the points ( 5, 2) and ( 6, 4) a. y = 2x - 8 c. y = 2x + 12 b.

o-na [289]

<span>( 5, 2) and ( 6, 4)
slope m = (4-2)/(6-5) = 2

y = mx + b
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so now you have slope m = 2 and y intercept b = -8

equation
y = 2x - 8

answer
</span><span>a. y = 2x - 8</span>

4 0

3 years ago

Read 2 more answers

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$