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3 years ago

How many solutions does this linear system have?

Mathematics

1 answer:

postnew [5]3 years ago

3 0

Answer:

no solution

Step-by-step explanation:

__________

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What is the length of b

oksian1 [2.3K]

Answer:

b = 24

Step-by-step explanation:

Concepts

The Pythagorean Theorem states that the sum of the squares of the two other sides on a right triangle is equal to hypotenuse (longest side) squared. It can be represented by the equation $a^2+b^2=c^2$ . We can also use this formula to solve for the other two legs in the right triangle.

Application

In this case, we're asked to find the length of b in the right triangle, given c as 26 and a as 10. Now, we just apply the formula and solve for b.

Solution

Step 1: Set up equation and simplify.

$10^2+b^2=26^2$
$100+b^2=676$

Step 2: Subtract 100 from both sides.

$100+b^2-100=676-100$
$b^2=576$

Step 3: Take square root of both sides.

$\sqrt{b^2} =\sqrt{576}$
$b=24$

Therefore, b = 24.

4 0

1 year ago

Read 2 more answers

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

PLEASE HELP MEEEEEEEE ILL MARK YOU BRAINLIEST

Andre45 [30]

Answer:

16.8

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the distance from the origin to point A graphed on the complex plane below?

ExtremeBDS [4]

Distance between two points is
Root of X2 - X1 squared + Y2 - Y1 squared
So here X2 is 0 X1 is 0 as the origin is 0,0
Root of Y2-Y1 squared is what we are left with
Root of -2- -3 squared
Root of 1 squared
Root of 1
Which is 1
Distance is 1

5 0

3 years ago

Select the correct answer

Basile [38]

Answer:

option b is the answer

Step-by-step explanation:

3 0

2 years ago