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Harman [31]
2 years ago
8

Please help me, im desperate

Mathematics
1 answer:
Arada [10]2 years ago
5 0

Answer: C. “BEC”

Step-by-step explanation:

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Eva took a taxi from her house to the airport. The taxi company charged a pic of feet of 3 dollars and 20 cents, plus 3 dollars
svetoff [14.1K]

Answer:

3x + 3.20 =33.20

Step-by-step explanation:

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3 years ago
HELP! Which triangles are congruent?
kati45 [8]

9514 1404 393

Answer:

  4.  A, B, C, and D

Step-by-step explanation:

Each right triangle has a short leg of 3 units and a long leg of 4 units. They are all congruent by the SAS congruence postulate.

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3 years ago
The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What
Simora [160]

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that \mu = 64.4, \sigma = 2.91

Sample of 50 women

This means that n = 50, s = \frac{2.91}{\sqrt{50}}

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}

Z = 1.46

Z = 1.46 has a p-value of 0.9279

1 - 0.9279 = 0.0721

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

8 0
3 years ago
Solve V=1/3bh for b base of the cone
Wittaler [7]

Answer:

V = 1/3 * b * h...divide both sides by 1/3h

V / (1/3h) = b

3V/h = b

Step-by-step explanation:

8 0
3 years ago
Hello. Is there anyone out there who can answer this for me? I truly appreciate it.
Kryger [21]
A. -1

(1,2) and (2,1)
slope = 2 -1 / 1 -2
slope = 1 / -1
slope = -1
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2 years ago
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