Question

Consider the following relation.

Answer 1

Answer:

(0,-1),(1,0),(2,1),(3,2)

Step-by-step explanation:

We are given that a relation

y=x+1y=x+1

We have to find the four points contained in the inverse

The given function is linear function

Therefore,

Domain of function=R

Range of function=R

x=y-1x=y−1

Now, replace x by y and y replace by x

y=x-1y=x−1

Now, substitute y=f^{-1}(x)=f

−1

(x)

f^{-1}(x)=x-1f

−1

(x)=x−1

It is linear function and defined for all real values.

Substitute x=0

f^{-1}(0)=-1f

−1

(0)=−1

Substitute x=1

f^{-1}(1)=1-1=0f

−1

(1)=1−1=0

f^{-1}(2)=2-1=1f

−1

(2)=2−1=1

f^{-1}(3)=3-1=2f

−1

(3)=3−1=2

Therefore, four points contained in the inverse (0,-1),(1,0),(2,1) and (3,2)