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pashok25 [27]
3 years ago
9

Chase baked 4/5 dozen brownies in 3 hours ? What is her average of baking per hour ?

Mathematics
1 answer:
loris [4]3 years ago
8 0

Answer:

3\frac{1}{5}brownies per hour

Step-by-step explanation:

     Given parameters:

Number of brownies = \frac{4}{5} of a dozen

Time taken  = 3hrs

Unknown:

Average baking per hour = ?

Solution:

The average baking per hour;

    This is a rate problem;

     Average baking per hour = \frac{number of baking}{time}

Number of brownies = \frac{4}{5} x 12  = \frac{48}{5}

 Average baking per hour = \frac{48}{\frac{5}{3} }  

                                            = \frac{48}{5} x \frac{1}{3}

                                             = \frac{16}{5}

                                            = 3\frac{1}{5}brownies per hour

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Answer:

What

Step-by-step explanation:

5 0
3 years ago
HELP with these questions
zlopas [31]

<u>Step-by-step explanation:</u>

transform the parent graph of f(x) = ln x        into f(x) = - ln (x - 4)  by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            0 = ln (x - 4)

            e^{0} = e^{ln (x - 4)}

             1 = x - 4

          <u> +4 </u>  <u>    +4 </u>

             5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            1 = ln (x - 4)

            e^{1} = e^{ln (x - 4)}

             e = x - 4

          <u> +4 </u>   <u>    +4 </u>

         e + 4 = x

          6.72 = x

(6.72, 1)

Domain: x - 4 > 0

                <u>  +4 </u>  <u>+4  </u>

               x       > 4

(4, ∞)

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No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ        into f(x) = - 3ˣ⁺⁵  by shifting the parent graph 5 units to the left and reflecting over the x-axis

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(-∞, ∞)

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(-∞, 0)

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5 0
3 years ago
Which equation has the correct sign on the product
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7 0
2 years ago
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4 0
3 years ago
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goldfiish [28.3K]

Answer:

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Step-by-step explanation:

1 Convert 2\frac{2}{5}2

5

2

​

 to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

c

b

​

=

c

ac+b

​

.

\frac{2\times 5+2}{5}\times 2\times 3\frac{1}{5}

5

2×5+2

​

×2×3

5

1

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2 Simplify  2\times 52×5  to  1010.

\frac{10+2}{5}\times 2\times 3\frac{1}{5}

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10+2

​

×2×3

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3 Simplify  10+210+2  to  1212.

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5

12

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×2×3

5

1

​

4 Convert 3\frac{1}{5}3

5

1

​

 to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

c

b

​

=

c

ac+b

​

.

\frac{12}{5}\times 2\times \frac{3\times 5+1}{5}

5

12

​

×2×

5

3×5+1

​

5 Simplify  3\times 53×5  to  1515.

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5

12

​

×2×

5

15+1

​

6 Simplify  15+115+1  to  1616.

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5

12

​

×2×

5

16

​

7 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

b

a

​

×

d

c

​

=

bd

ac

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.

\frac{12\times 2\times 16}{5\times 5}

5×5

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​

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​

8 0
2 years ago
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