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pashok25 [27]
3 years ago
9

Chase baked 4/5 dozen brownies in 3 hours ? What is her average of baking per hour ?

Mathematics
1 answer:
loris [4]3 years ago
8 0

Answer:

3\frac{1}{5}brownies per hour

Step-by-step explanation:

     Given parameters:

Number of brownies = \frac{4}{5} of a dozen

Time taken  = 3hrs

Unknown:

Average baking per hour = ?

Solution:

The average baking per hour;

    This is a rate problem;

     Average baking per hour = \frac{number of baking}{time}

Number of brownies = \frac{4}{5} x 12  = \frac{48}{5}

 Average baking per hour = \frac{48}{\frac{5}{3} }  

                                            = \frac{48}{5} x \frac{1}{3}

                                             = \frac{16}{5}

                                            = 3\frac{1}{5}brownies per hour

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Delvig [45]
 2        2(5)        10
---- = --------- = -------
 5        5(5)        25

hope this helps :)
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rodikova [14]

Answer:

x = 18 and y = 6√10

Step-by-step explanation:

First using pythagoras theorem on the small triangle

h² = 6² + 2²

h² = 36 + 4

h² = 40

h= √40

h = √4 * 10

h = 2√10

Using the similarity theorem;

y/2√10 = 6/2

y/√10 = 6

y = 6√10

To get x we will use the pythagoras theorem

y² = x²+6²

(6√10)² = x² + 36

360 = x² + 36

x² = 360 - 36

x² = 324

x = 18

Hence x = 18 and y = 6√10

5 0
3 years ago
A manager wants to select one group of 4 people from his 28 assistants.
Keith_Richards [23]

There are, 20475 different groups are possible if the manager wants to select one group of 4 people from his 28 assistants.

<h3>What is permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have:

A manager wants to select one group of 4 people from his 28 assistants.

The total number of groups possible = C(28, 4)

= \rm \dfrac{28!}{4!(28-4)!}

After calculating:

= 20475

Thus, there are, 20475 different groups are possible if the manager wants to select one group of 4 people from his 28 assistants.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ1

8 0
2 years ago
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