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pashok25 [27]
3 years ago
9

Chase baked 4/5 dozen brownies in 3 hours ? What is her average of baking per hour ?

Mathematics
1 answer:
loris [4]3 years ago
8 0

Answer:

3\frac{1}{5}brownies per hour

Step-by-step explanation:

     Given parameters:

Number of brownies = \frac{4}{5} of a dozen

Time taken  = 3hrs

Unknown:

Average baking per hour = ?

Solution:

The average baking per hour;

    This is a rate problem;

     Average baking per hour = \frac{number of baking}{time}

Number of brownies = \frac{4}{5} x 12  = \frac{48}{5}

 Average baking per hour = \frac{48}{\frac{5}{3} }  

                                            = \frac{48}{5} x \frac{1}{3}

                                             = \frac{16}{5}

                                            = 3\frac{1}{5}brownies per hour

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VashaNatasha [74]

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

8 0
2 years ago
In a triangle, the measure of the first angle is 24 degrees more than the measure of the second angle. The measure of the third
insens350 [35]

Answer:

104°

Step-by-step explanation:

let the second angle be x , then

the first angle is x + 24

the third angle is 4x , thus summing and equating to 180

x + x + 24 + 4x = 180, that is

6x + 24 = 180 ( subtract 24 from both sides )

6x = 156 ( divide both sides by 6 )

x = 26

Thus largest angle = 4x = 4 × 26 = 104°

6 0
2 years ago
10x=-3-8x^2<br> Solve by factoring
GrogVix [38]

Answer:

10 x = -3 -8 x²

Step-by-step explanation:

6 0
3 years ago
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Answer:

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4 0
2 years ago
Which of the following are solutions to the equation below?
scoundrel [369]

Answer:

The correct options for the solution values are:

  • x=2\sqrt{2}-5
  • x=-2\sqrt{2}-5

Step-by-step explanation:

Given the expression

x^2+10x+25=8

Subtract 25 from both sides

x^2+10x+25-25=8-25

Simplify

x^2+10x=-17

Add 25 or 5² to both sides

x^2+10x+5^2=8

as

x^2+10x+5^2=\left(x+5\right)^2

so the expression becomes

\left(x+5\right)^2=8

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x+5=\sqrt{8}

Subtract 5 from both sides

x+5-5=2\sqrt{2}-5

x=2\sqrt{2}-5

solve

x+5=-\sqrt{8}

Subtract 5 from both sides

x+5-5=-2\sqrt{2}-5

x=-2\sqrt{2}-5

Therefore, the solution to the equation

x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5

Hence, the correct options for the solution values are:

  • x=2\sqrt{2}-5
  • x=-2\sqrt{2}-5

6 0
3 years ago
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