Answer:
0.7x/0.8y = x/y * 0.7/0.8 = x/y * 0.875
So the fraction is reduced by 12.5%
Well. If you get 29% of 5 cars that is 145%. This was a little confusing but I am defiantly sure it is correct. I like to use simpler numbers to see if I am doing the work right. So I said if he has a 50 % likely hood to find a car that was expired and had 1 car. It would be 50 percent. Now if he had 2nt got it the first time it would be a 100 % chance to find the car expired . Hope I didn’t co fuse you more
36 miles per hour if he ran 12 miles in 20 minuets and there are 60 minuets in an hour, then multiply the # by 3
