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3 years ago

13

WORK OUT (810^-3)(2*10^-4)

2 answers:

Talja [164]3 years ago

6 0

(8 x 10^-3) x (2 x 10^-4)

10^-3 = 1/10^3, which is equal to 1/1000

10^-4 = 1/10^4, which is equal to 1/10000

8 x 1/1000 = 8/1000

2 x 1/10000 = 2/10000

(I’m turning these into decimals because it’s easier lol)

0.008 x 0.0002 = 0.0000016

In scientific notation, it is 16 x 10^-7

Hope this helped!

frutty [35]3 years ago

4 0

-First we have to work out what’s in parenthesis.
(8*10^-3)=(8*0.001)=0.008

-This is for the second parenthesis
(2*10^-4)=(2*0.0001)=0.0002

-Now we multiply them together

ANSWER: 0.0000016

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Step-by-step explanation:

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Katen [24]

$\green{\large\underline{\sf{Solution-}}}$

<u>Given expression is </u>

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

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