*urgent* Determine whether this quadrilateral must be a parallelogram
1 answer:
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Answer:
A) Area as function of H ,
F'(a) = 2 +H
B) Area of triangle with height 6ft = 30 ft²
Step-by-step explanation:
Given as for a triangle ,
Let the height of triangle = H ft
And base = 4 ft + H ft
Now area of triangle = × height × base
F (a) = × H × ( 4ft + H ft)
Or, F (a) = × ( 4H + H² )
Now, here Area is function of height ,
So , F'(a) = (4 + 2H)
Hence Area as function of H ,
F'(a) = 2 +H
Now For height = 6 ft
Area of triangle = × height × base
= × H × ( 4ft + H ft)
= × ( 4H + H² )
= × ( 24 + 36 )
= × ( 60 )
= 30 ft²
Hence Area of triangle with height 6ft = 30 ft² Answer