Answer:
![(D)E[ X ] =np.](https://tex.z-dn.net/?f=%28D%29E%5B%20X%20%5D%20%3Dnp.)
Step-by-step explanation:
Given a binomial experiment with n trials and probability of success p,


Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

Now,

Substituting,

Factoring out the n and one p from the above expression:

Representing k=x-1 in the above gives us:

This can then be written by the Binomial Formula as:
![E[ X ] = (np) (p +(1 - p))^{n -1 }= np.](https://tex.z-dn.net/?f=E%5B%20X%20%5D%20%3D%20%28np%29%20%28p%20%2B%281%20-%20p%29%29%5E%7Bn%20-1%20%7D%3D%20np.)
Answer:
thx
Step-by-step explanation:
Answer:
im pretty sure its 152, im sorry if im wrong, i took 180 and subtracted 180 - 16 - 12 and got that soooo
Step-by-step explanation:
Answer:
The Answer would be 4n
Step-by-step explanation:
Since Marcus ran four times as far this week, we need to know how far he ran last week in order to solve this expression. Since we do not know this information it becomes our variable (n). From the statement we can also infer that there is multiplication since he states the word "times". Therefore our Algebraic Expression would be the following.
P = 4n
P being distance ran by Marcus, and n being distance ran last week by Marcus.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
0.186
Step-by-step explanation:
6.2
<u>x 0.0</u><u>3</u>
6
1
6.2
<u>x 0.0</u><u>3</u> since 6*3=18, we have to carry the 1
86
1
6.2
<u>x 0.0</u><u>3</u>
186
6.2
<u>x 0.</u><u>0</u><u>3</u>
186
0
6.2
<u>x 0.</u><u>0</u><u>3</u>
186
00
6.2
<u>x </u><u>0</u><u>.03</u>
186
00
0
6.2
<u>x </u><u>0</u><u>.03</u>
186
+ 00 add the partial products
<u> 0</u><u>0 </u>
00186
6.2
<u>x 0.</u><u>03</u><u> </u> count how many digits are after the decimal point from each factor =3 and place in product
186
+ 00
<u> 00 </u>
00.186=0.186
<em>answer=0.186</em>