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konstantin123 [22]
3 years ago
10

Please help i’m struggling so much

Mathematics
2 answers:
Lesechka [4]3 years ago
7 0
3 should be the answer
skelet666 [1.2K]3 years ago
7 0

Answer:

3 will be the answer.

Step-by-step explanation:

Hope it's help you ♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c
natali 33 [55]

Answer:  By the slope formula.

Step-by-step explanation:

Given: ABC is a triangle (shown below),

In which A≡(6,8), B≡(2,2) and C≡(8,4)

And, D and E are the mid points of the line segments AB and BC respectively.

Prove: DE║AC and DE = AC/2

Proof:

Since, And, D and E are the mid points of the line segments AB and BC respectively.

Therefore, By mid point theorem,

coordinate of D are (\frac{2+6}{2} , \frac{2+8}{2} ) = (\frac{8}{2} , \frac{10}{2} )= (4,5)

Coordinate of E are  (\frac{2+8}{2} , \frac{2+4}{2} ) = (\frac{10}{2} , \frac{6}{2} )= (5,3)

By the distance formula,

DE=\sqrt{(5-4)^2+(3-5)^2}=\sqrt{5}

AC=\sqrt{(8-6)^2+(4-8)^2}=2\sqrt{5}

By the slope formula,

Slope of AC = \frac{4-8}{8-6} = \frac{-4}{2} = -2

Slope of DE =  \frac{3-5}{5-4} = \frac{-2}{1} = -2


            Statement                                              Reason

1. The coordinate of D are (4,5)  and           1. By the midpoint formula

the coordinate of  E are (5,3)

2. The length of DE = √5                            2. By the Distance formula

The length AC = 2√5 ⇒ Segment DE

is half the length of segment AC

3. The slope of DE = -2 and the                3. By the slope formula

slope of AC = -2

4. DE║AC                                                   4. Slopes of parallel lines are equal


7 0
3 years ago
Read 2 more answers
6 − x = −12<br> please answer
lorasvet [3.4K]

Answer:

x=18

Step-by-step explanation:

6-x=-12

Subtracting 6 from both sides

-x=-12-6

-x= -18

Dividing both sides by -1

x=18

6 0
3 years ago
Read 2 more answers
Which of the following shows 2x3y-3x2+7yx-12y written in standard form
AysviL [449]
2x^(3)y+7xy-3x^(2)-12y

is in standard form
3 0
3 years ago
The length of a rectangle is six times its width. If the area of the rectangle is 384^2, find its perimeter.
Leno4ka [110]

Answer:

Perimeter, P = 112 meters

Step-by-step explanation:

  • Let the length of the rectangle be L.
  • Let the width of the rectangle be W.

Translating the word problem into an algebraic expression, we have;

L = 6W  ...... equation 1

<u>Given the following data;</u>

  • Area of rectangle = 384 m²

To find the perimeter of the rectangle;

First of all, we would determine the dimensions of the rectangle using its area.

Mathematically, the area of a rectangle is given by the formula;

Area of rectangle = LW  ..... equation 2

Substituting eqn 1 into eqn 2, we have;

384 = 6W(W)

384 = 6W²

Dividing both sides by 6, we have;

W² = 384/6

W² = 64

Taking the square root of both sides, we have;

W = √64

Width, W = 8 meters

Next, we would find the length;

L = 6W

L = 6 * 8

Length, L = 48 meters

Lastly, we would determine the perimeter of the rectangle using the above dimensions;

Mathematically, the perimeter of a rectangle is given by the formula;

Perimeter = 2(L + W)

Substituting the values into the formula, we have;

Perimeter, P = 2(48 + 8)

Perimeter, P = 2(56)

<em>Perimeter, P = 112 meters</em>

4 0
3 years ago
The diagonal of a square unit is x units. What is the Area of the square in terms of x
ohaa [14]
Area of square = a^2 
but
a^2 = d^2 / 2 = x^2 / 2

so area = x^2/2

answer is A. x^2 / 2 or 1/2 (x)^2

5 0
3 years ago
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