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2 years ago

Work out the area of triangle ABC 2root5cm 3root2cm root2cm

Mathematics

1 answer:

andrey2020 [161]2 years ago

3 0

35

Mark brainliest please

Hope this helps you out

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Help plz:)))I’ll mark u Brainliest

Stolb23 [73]

Answer:

x=20

Step-by-step explanation:

hope this helps

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3 years ago

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What is 99 times 99 whoever gets write get brainiest

son4ous [18]

Answer:

9,801

Step-by-step explanation:

99*99=9,801

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3 years ago

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A like has two-fold Symmetry

Vikki [24]

Answer:

yes

Step-by-step explanation:

5 0

3 years ago

Stuck on question 1, can anyone help???

poizon [28]

'A' is the square root of 25. That's 5, so take A=5 with you
as you go to the next step.

B is A³. A³ means (A x A x A). We know that 'A' is 5, so 'B' is (5x 5 x 5) = 125 .
Take B=125 with you to the next step.

'C' is B - 25. We know that 'B' is 125. So C = (125 - 25) = 100 .
Take C=100 with you to the next step.

'D' is the square root of 'C'. We know that C=100, so D = √100 .
The square root of 100 is 10, so D=10.
Take D=10 with you to the next step .

'E' is D+39. We know that D=10. So E=(10+39) = 49 .
Take E=49 with you to the last step.

'F' is the square root of 'E'. We know that E=49.

7 0

3 years ago

Read 2 more answers

A group of 54 college students from a certain liberal arts college were randomly sampled and asked about the number of alcoholic

Ket [755]

Answer:

$t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601$

P-value

First we find the degrees of freedom given by:

$df = n-1= 54-1=53$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{53}>0.9601)=0.3414$

Step-by-step explanation:

Data given and notation

$\bar X=5.25$ represent the sample mean

$s=3.98$ represent the sample standard deviation

$n=54$ sample size

$\mu_o =4.73$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean differs from 4.73, the system of hypothesis would be:

Null hypothesis: $\mu =4.73$

Alternative hypothesis: $\mu \neq 4.73$

Since we know don't the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601$

P-value

First we find the degrees of freedom given by:

$df = n-1= 54-1=53$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{53}>0.9601)=0.3414$

7 0

3 years ago