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Norma-Jean [14]
2 years ago
11

2 lines intersect. A line with points R, S, U intersects a line with points V, S, T at point S.

Mathematics
1 answer:
Dima020 [189]2 years ago
7 0

Step-by-step explanation:

here is your answer

enjoy

thanks to another users to give this answer

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What is the exact volume of the cone? Radius is 9cm and the height is 6cm.
masha68 [24]

Answer:


The volume of the cone is 508.94

8 0
4 years ago
The cereal box shown below is a rectangular prism.
joja [24]

Answer:

Surface area is found:

Surface Area = 1700 cm²

Step-by-step explanation:

(The cereal box is shown in the ATTACHMENT)

The surface area of a rectangular prism can be found by added the areas of all 6 sides of the rectangular prism.

L = length = 20 cm

H = height = 30 cm

W = Width = 5 cm

Side 1:

A(1) = L×H

A(1) = 20×30

A(1) = 600 cm²

Side 2:

As the measurements of the side at the back of side 1 has the same measurement of side 1. then:

A(2) = 600 cm²

Side 3:

A(3) = L×W

A(3) = 20×5

A(3) = 100 cm²

Side 4:

As the measurements of the side at the back of side 4 has the same measurement of side 4. then:

A(4) = 100 cm²

Side 5:

A(5) = H×W

A(5) = 30×5

A(5) = 150 cm²

Side 6:

As the measurements of the side at the back of side 5 has the same measurement of side 5. then:

A(6) = 150 cm²

Surface Area:

Adding areas of all the sides

A(1) + A(2) + A(3) +A(4) + A(5) + A(6) = 600 + 600 + 100 +100 + 150 +150

Surface Area = 1700 cm²

3 0
3 years ago
In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p
skelet666 [1.2K]

Answer:

\mathbf{P(X=5) =0.0888}    

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

\mathtt{P(X=x) =(^{n}_{x} )   \  \pi^x \  (1-\pi)^{n-x}}

\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} )   \  \pi^x \  (1-\pi)^{n-x}}

where;

n = 8 and π = 0.36

For x = 5

The probability \mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} )   \  0.36^5 \  (1-0.36)^{8-5}}

\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} )   \  0.36^5 \  (0.64)^{3}}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =({8 \times 7 } )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =0.0887645}

\mathbf{P(X=5) =0.0888}     to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5)\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})

{P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times  (0.36)^0  \times  (1-0.36)^8  \ )  +  \dfrac{8!}{1!(7!)} \times  (0.36)^1  \times  (1-0.36)^7  \ +\dfrac{8!}{2!(6!)} \times  (0.36)^2  \times  (1-0.36)^6  \ +  \dfrac{8!}{3!(5!)} \times  (0.36)^3  \times  (1-0.36)^5 +  \dfrac{8!}{4!(4!)} \times  (0.36)^4  \times  (1-0.36)^4  \  +  \dfrac{8!}{5!(3!)} \times  (0.36)^5  \times  (1-0.36)^3  \ )

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1  - P( x  ≤ 5 )

P ( x ≥ 6) = 1  - 0.9707

P ( x ≥ 6) = 0.0293

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Answer: A.

Step-by-step explanation:

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