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2 years ago

2 lines intersect. A line with points R, S, U intersects a line with points V, S, T at point S.

Mathematics

1 answer:

Dima020 [189]2 years ago

7 0

Step-by-step explanation:

here is your answer

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thanks to another users to give this answer

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Help meh...............

SSSSS [86.1K]

Answer:

Angles 6, 4, and 2 are congruent to angle 8.

Step-by-step explanation:

By the Opposite Angles Theorem, angle 6 is congruent to angle 8.

By the Corresponding Angles Theorem, angle 4 is congruent to angle 8.

By the Corresponding Angles Theorem, angle 2 is congruent to angle 6, and angle 6 is congruent to angle 8, so angle 2 is congruent to angle 8 by the Transitive Property.

7 0

2 years ago

What are the zeros of 2x^2+17x=-21

enyata [817]

$2x^2+17x+21=0\\D=17^2-4*2*21=121=11^2\\x_1=\frac{-17+11}{4} =-1,5\\x_2=\frac{-17-11}{4} =-7$

zeros of 2x^2+17x=-21 are (-7;0) and (-1,5)

P.S. Hello from Russia

3 0

3 years ago

Evaluate 4 square root 9 square root 9 over 4 square root 9^5

Sedbober [7]

$\frac{\sqrt[4]{9}.\sqrt{9}}{\sqrt[4]{9^5}}$

$\frac{9^\frac{1}{4}.9^\frac{1}{2}}{9^\frac{5}{4}}$

$\frac{9^\frac{6}{8}}{9^\frac{5}{4}}$

$9^{\frac{6}{8}-\frac{5}{4}}$

$9^\frac{-1}{2}$

8 0

3 years ago

Please help for brainliest

evablogger [386]

I think u have to multiply both side by 1x to get rid of the x so the answer is the first one, 1

5 0

3 years ago

F(x)=-9x^2-2x and g(x)=-3x^2+6x-9, find (f-g)(x) and (f-g)(-4)

Alona [7]

Answer:

(f - g)(x)= - 6 {x}^{2} - 8x + 9

(f - g)(-4!)= - 55

Step-by-step explanation:

$f(x) = - 9 {x}^{2} - 2x, \: \: g(x) = - 3 {x}^{2} + 6x - 9 \\ (f - g)(x) = f(x) - g(x) \\ = - 9 {x}^{2} - 2x - (- 3 {x}^{2} + 6x - 9) \\ = - 9 {x}^{2} - 2x + 3 {x}^{2} - 6x + 9 \\ \purple{ \boxed{ \bold{(f - g)(x)= - 6 {x}^{2} - 8x + 9}}} \\ (f - g)( - 4)= - 6 {( -4 )}^{2} - 8( - 4) + 9 \\ = - 6 \times 16 + 32 + 9 \\ = - 96 + 41 \\ \red{ \boxed{ \bold{(f - g)( - 4)= - 55}}}$

6 0

3 years ago