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2 years ago

Plz help due tomorrow

Mathematics

2 answers:

Ede4ka [16]2 years ago

8 0

Okay the equation is 1/6x + 1/30

It is asking us to plug in 1/5 so let’s plug it in

1/6(1/5) + 1/30 = 1/30 + 1/30 = 2/30

So we reduce the fraction and the answer is 1/15

Lelechka [254]2 years ago

4 0

Answer:

Step-by-step explanation:

1/6 x 1/5 + 1/30

= 1/30 + 1/30

= 2/30

=1/15

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2 years ago

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2 years ago

Select all possible values for x in the equation x^3=375?

Helga [31]

<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

To solve the problem, we need to remember the following properties of the exponents and roots:

$a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}$

Then, we are given the expression:

$x^{3}=375$

So, finding "x", we have:

$x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}$

Hence, the possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

Have a nice day!

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3 years ago