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Tju [1.3M]
3 years ago
9

X + (-x) = 0 help me plz​

Mathematics
1 answer:
andriy [413]3 years ago
7 0

x+-x = 0

x-x = 0

0 = 0

infintely many solutions

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Which equation in point-slope form describes the line through points (4, –4) and (1, 2)?
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Step-by-step explanation:

<em>Given </em><em>points </em><em>(</em><em>4</em><em> </em><em>,</em><em> </em><em>-</em><em>4</em><em>)</em><em> </em><em> </em><em>and </em><em>(</em><em> </em><em>1</em><em>,</em><em> </em><em>2</em><em>)</em>

<em>First </em><em>calculating </em><em>slope </em><em>(</em><em>m) </em><em> </em>

<em>=</em><em>(</em><em> </em><em>y2</em><em> </em><em>-</em><em> </em><em>y1) </em><em>/</em><em>(</em><em> </em><em>x2 </em><em>-</em><em>x1) </em>

<em>=</em><em> </em><em>(</em><em> </em><em>2</em><em> </em><em>+</em><em> </em><em>4</em><em>)</em><em> </em><em>/</em><em> </em><em>(</em><em>1</em><em>-</em><em>4</em><em>)</em>

<em>=</em><em> </em><em>6</em><em>/</em><em> </em><em>-</em><em>3</em>

<em>=</em><em> </em><em>-</em><em>2</em>

<em>Now</em>

<em>The </em><em>equation </em><em>in </em><em>point </em><em>slope </em><em>form</em>

<em>y </em><em>-</em><em> </em><em>y1</em><em> </em><em>=</em><em> </em><em>m </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>x1) </em>

<em>y </em><em>+</em><em> </em><em>4</em><em> </em><em>=</em><em> </em><em>-</em><em>2</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>4</em><em>)</em>

<em>y </em><em>+</em><em> </em><em>4</em><em> </em><em>=</em><em> </em><em>-</em><em>2</em><em>x</em><em> </em><em>+</em><em> </em><em>8</em>

<em>2x </em><em>+</em><em> </em><em>y </em><em>-</em><em> </em><em>8</em><em> </em><em>+</em><em> </em><em>4</em><em> </em><em>=</em><em> </em><em>0</em>

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6 0
3 years ago
I need help n explainnnn please ​
kobusy [5.1K]

The Correct option is D). y=1x+1 And y=2x+2

Step-by-step explanation:

The equation of a line is given as y=mx+c.

where m=slope of line and c=y intercept

The slope of line is given as  m=\frac{(Y2-Y1)}{(X2-X1)}

Solving for Redline:

From the given graph, redline passes through (-1,0) and (0,1)

The slope of Redline is  m=\frac{(Y2-Y1)}{(X2-X1)}

The slope of Redline is  m=\frac{(1-0)}{(0-(-1))}

The slope of Redline is  m=(1)

And Y-intercept is 1

The equation of a Redline is given as y=1x+1

Solving for Blue-line:

From the given graph, Blue-line passes through (-1,0) and (0,2)

The slope of Blue-line is  m=\frac{(Y2-Y1)}{(X2-X1)}

The slope of Blue-line is  m=\frac{(2-0)}{(0-(-1))}

The slope of Blue-line is  m=(2)

And Y-intercept is 2

The equation of a Blue-line is given as y=2x+2

The Correct option is D). y=1x+1 And y=2x+2

7 0
3 years ago
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