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3 years ago

The coordinates of the vertices of quadrilateral ABCD are A(−5, 1), B(−2, 5), C(5, 3), and D(2, −1).

Mathematics

1 answer:

Vaselesa [24]3 years ago

6 0

Answer:

mab-2

mbc1/2

mcd-3/4

mad-3/4

Step-by-step explanation:

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What is the surface area of this square pyramid

JulsSmile [24]

Answer:

Surface area of square pyramid shown in picture:

A = area of 4 triangles + area of square

= 4 x 4 x 3 x (1/2) + 3 x 3

= 33 (ft)

=> Option 4 (last one) is correct

Hope this helps!

3 0

3 years ago

Raul plans to run 30 miles this week. He wants to run the same number of miles each day of the week. He says he will run 7/30 mi

dmitriy555 [2]

No, because if he runs 7/30 mile each day he will run 210 miles each week because he is running 30 miles every day so he has to run 7/4.28 miles each day of the week to get 30 miles each week.

3 0

2 years ago

PLEASE HELP

Readme [11.4K]

Answer:

x=5

Step-by-step explanation:

5 0

4 years ago

WHO CAN solve it Please !

Mariulka [41]

Answer:

a) True

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

Step-by-step explanation:

Step(i):-

Given that the definite integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha$

we know that the trigonometric formula

sin²∝+cos²∝ = 1

cos²∝ = 1-sin²∝

step(ii):-

Now the integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha$

= $\int\limits^\pi _0 {cos\alpha } \, dx$

Now, Integrating

$= ( sin\alpha )_{0} ^{\pi }$

= sin π - sin 0

= 0-0

= 0

Final answer:-

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

5 0

3 years ago

Is |-6| a negative integer

stiv31 [10]

Answer:

NO. |-6| = 6 - a positive integer

Step-by-step explanation:

|a| = a for a ≥ 0

examples

|2| = 2, |0| = 0, |0.56| = 0.56

|a| = -a for a < 0

examples

|-2| = -(-2) = 2, |-100| = -(-100) = 100, |-0.25| = 0.25

Therefore your answer:

|-6| = 6 > 0

3 0

3 years ago