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Varvara68 [4.7K]
3 years ago
15

At the hardware store, you purchased a box of nails for 17 dollar. You had a coupon that took off 20% from the nails. Sales tax

is 6%. What is the total cost for the nails. Must show work
Mathematics
2 answers:
Vikentia [17]3 years ago
5 0
(17-.2(17))+(17+.06(17))

Kisachek [45]3 years ago
5 0
<span><span><span>   ~~~~
17−<span><span>(0.2)</span><span>(17)</span></span></span>+17</span>+<span><span>(0.06)</span><span>(17)</span></span></span><span>=<span><span><span>17−3.4</span>+17</span>+<span><span>(0.06)</span><span>(17)</span></span></span></span><span>=<span><span>13.6+17</span>+<span><span>(0.06)</span><span>(17)</span></span></span></span><span>=<span><span>13.6+17</span>+1.02</span></span><span>=<span>13.6+18.02</span></span><span>=<span>31.62</span></span>
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TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streamin
choli [55]

Answer:

a) The 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

b) n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51  

And rounded up we have that n=1831

Step-by-step explanation:

Data given and notation  

n=2341 represent the random sample taken    

X represent the people that they have watched digitally streamed TV programming on some type of device

\hat p=0.55 estimated proportion of people that they have watched digitally streamed TV programming on some type of device  

\alpha=0.01 represent the significance level

Confidence =0.99 or 99%

z would represent the statistic for the confidence interval  

p= population proportion of people that they have watched digitally streamed TV programming on some type of device

The population proportion present the following distribution:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}}

Part a) Confidence interval

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.55 - 2.58 \sqrt{\frac{0.55(1-0.55)}{2341}}=0.523

0.55 + 2.58 \sqrt{\frac{0.55(1-0.55)}{2341}}=0.577

And the 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

Part b) What sample size would be required for the width of a 99% CI to be at most 0.03 irrespective of the value of p??

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51  

And rounded up we have that n=1831

8 0
4 years ago
What word expression matches 3+(4×12)
AnnyKZ [126]

The Word Expression Would Be:

<em><u>Four times twelve plus three</u></em>

Any Additional Questions? Comment Below!

<em><u>-AnonymousGiantsFan</u></em>

8 0
3 years ago
662/3% of what number is 320?
sweet [91]
It's similar to example above,I hope you get it.

4 0
4 years ago
Answers this plz I need help
san4es73 [151]

Answer:

y=2x+5

Step-by-step explanation:

u find the slope and since the y intercept is (0,5), that's the b value

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3 years ago
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Iteru [2.4K]

Answer:

The equation of this line would be y = 4x - 5

Step-by-step explanation:

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y - y1 = m(x - x1)

y - 3 = 4(x - 2)

y - 3 = 4x - 8

y = 4x - 5

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4 years ago
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