Answer:
<u>The cube root parent function:</u>
- f(x) =
![\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D)
<u>Horizontally stretched by a factor of 4:</u>
- g(x) → f(1/4x) =
![\sqrt[3]{1/4x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1%2F4x%7D)
<u>Translated 5 units right:</u>
- h(x) → g(x - 5) =
![\sqrt[3]{1/4x - 5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1%2F4x%20-%205%7D)
<u>Translated 3 units up:</u>
- k(x) → h(x) + 3 =
![\sqrt[3]{1/4x - 5} + 3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1%2F4x%20-%205%7D%20%2B%203)
Answer:
The largest would be -1/3
Step-by-step explanation:
Answer:
Part A) The measure of arc DF is 129°
Part B) The measure of arc DEB is 270°
Part C) The measure of arc BEC is 321°
Step-by-step explanation:
Part A) What would be the measure of arc DF?
we know that
CF is a diameter
so
The measure of arc CDEF is equal to 180 degrees
arc CD+arc DE+arc EF=180°
substitute the given values
51°+90°+arc EF=180°
arc EF=180°-(51°+90°)=39°
arc DF=arc DE+arc EF
arc DF=90°+39°=129°
Part B) What would be the measure of arc DEB?
we know that
arc DEB=arc DE+arc EFB
we have
arc DE=90°
arc EFB=180° -----> because EB is a diameter
substitute
arc DEB=90°+180°=270° -----> 3/4 of a circle
Part C) What would be the measure of arc BEC?
we know that
arc BEC=arc DEB+arc CD
we have
arc DEB=270°
arc CD=51°
substitute
arc BEC=270°+51°=321°
Answer:
120 MW/hour
Step-by-step explanation:
The formula of the average rate of change between two points in a function is:
Average rate of change (ARC) = f(x2) -f(x1)/(x2-x1)
Let's think the power demad as a function d(x) depending of the hour of the day, so the variable x= hour of the day.
Now we have:
d(5)= 1600
d(8)= 1960
If we apply the mentioned ARC formula = [d(8)-d(5)] MW/(8-5)hour= (1960-1600)MW/3hour= 360/3=120 MW/Hour
56. and 1.6^4
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