Answer:
sometimes
Step-by-step explanation:when a >b?
ax+y=8
bx + y = 5
always
sometimes
O
never
To solve this problem we must know that when any two lines intersect , a pair of opposite angles from the figure Will be equal
so that means that

we can subtract twenty from each side


now we can subtract like terms

so we can get the final answer as
Answer:
The distance between points A and B is 13
Step-by-step explanation:
We need to find distance between points A and B
Looking at the graph,
Point A : (2,6) and Point B: (-3,-6)
We need to find the distance between these points.
The formula used is: 
We have Points A : (2,6) and B: (-3,-6)
So, 
Putting values in formula and finding distance

So, the distance between points A and B is 13
Answer:
The length of the hypotenuse is 2 square root of 13 ⇒ c
Step-by-step explanation:
The rule of the area of the right triangle is A =
× leg1 × leg2, where
leg1 and leg2 are the sides of the right angle
∵ The area of a right triangle is 12 in²
∵ The ratio of the length of its legs is 2: 3
→ Let leg1 = 2x and leg2 = 3x
∵ leg1 = 2x and leg2 = 3x
→ Substitute them in the rule of the area above
∴ 12 =
× 2x × 3x
∵ 2x × 3x = 6x²
∴ 12 =
× 6x²
∴ 12 = 3x²
→ Divide both sides by 3 to find x²
∴ 4 = x²
→ Take √ for both sides
∴ x = 2
→ Substitute x in the expressions of leg1 and leg2 to find them
∴ leg1 = 2(2) = 4 inches
∴ leg2 = 3(2) = 6 inches
∵ hypotenuse =
∴ hypotenuse = 
∵ The simplest form of
= 2
∴ The length of the hypotenuse = 2
inches
The answer can be readily calculated using a single variable, x:
Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%
The problem is then stated as:
(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000
Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.