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3 years ago

(HELP ASAP!)Which postulate or theorem proves △HJZ∼△WJR ?

Mathematics

1 answer:

Tomtit [17]3 years ago

8 0

Answer:

SAS Similarity Theorem

Step-by-step explanation:

we know that

<u>SAS Similarity Theorem</u>: States that if two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar

In this problem

∠HJZ=∠RJW ----> by vertical angles

and

WJ/HJ=JR/JZ

substitute the values

8/4=6/3

2=2 ----> is true

Two sides of triangle HJZ are proportional with the two corresponding sides of triangle WJR and the included angle is congruent

therefore

Triangles are similar by SAS Similarity Theorem

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PtichkaEL [24]

Answer:

180 degrees per second.

Step-by-step explanation:

We have been given a graph that shows the distance covered by a tire or angular velocity of a tire with respect to the number of seconds (x).

Since we know that a tire is a circle and the measure of all the angles of a circle equals to 360 degrees.

We can see from our given graph that the tire completes one rotation in 2 seconds (2.5-0.5), so the distance covered by tire in two seconds will be 360 degrees. This means that the tire turns 360 degrees in each 2 seconds.

$\text{Degrees turned by tire in 2 seconds}=\frac{360^o}{2\text{ seconds}}$

As we are asked to find the degree change by tire per second so we will find the unit rate such that we will have 1 in our denominator. By dividing our numerator and denominator by 2 we will get,

$\text{Degrees turned by tire in every second}=\frac{180^o}{\text{ second}}$

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3 years ago

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Find the length of the tangent segment AB to the circles centered at O and O' whose radii are a and b respectively when the circ

bixtya [17]

Answer:

$AB=2\sqrt{ab}$

Step-by-step explanation:

From figure,

$OA=a, \quad \quad O'B=b\\\Rightarrow OO'= (a+b) \quad \quad \text{and}\quad OD=(a-b)$

In triangle $OO'D$

$(OO')^2=(OD)^2+(O' D)^2$

$\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]$

Hence, $AB=2\sqrt{ab}$

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3 years ago

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DedPeter [7]

Answer:

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Step-by-step explanation:

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10kg 20kg 24kg ?kg plz answer this for me

luda_lava [24]

Answer:

27KG

Step-by-step explanation:

Mouse- M , Cat - C, Dog - D

M + C = 10 ----- (1)

M + D = 20 -------(2)

C + D = 24 --------(3)

(1) - (2) => C - D = -10 ---- (4)

(3) + (4) => 2C = 14

=> C = 7

Substitute C in (1) => M + 7 = 10

=> M = 3

Substitute M in (2) => 3 + D = 20

=> D = 17

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3 years ago

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use the chain rule

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