Either way you do it you always get 1500 as your answer.
Answer:
About 8.6 units.
If you count up and sideways, it would be 12, but then there is some stuff we need to calculate at the end because it's not fully.
90-30=60 Hoped this helped
Answer:
The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A study suggested that children between the ages of 6 and 11 in the US have an average weightof 74 lbs, with a standard deviation of 2.7 lbs.
This means that 
What proportion of childrenin this age range between 70 lbs and 85 lbs.
This is the pvalue of Z when X = 85 subtracted by the pvalue of Z when X = 70. So
X = 85



has a pvalue of 1
X = 70



has a pvalue of 0.0694
1 - 0.0694 = 0.9306
The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.
The slope is:
.
________________________________________________________Note:________________________________________________________slope = rise/ run = 15 ft/ 1000 ft ;
= 15/1000 = (15÷15) / (1000÷15) ;
= 1/ (200/3) = 1* (3/200) =
[tex] \frac{3}{200} [/tex] .
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